已知数列{an}的通项公式an=1083n+1(n∈N*),设其前n项和为Sn,则使Sn<-4成立的最小自然数n等于( ) A. 83 B. 82 C. 81 D. 80
FOXL2 is an evolutionally conserved transcription factor, and its mutations cause blepharophimosis, ptosis, and epicanthus inversus syndrome (BPES), wherein affected females display eyelid defects and premature ovarian failure (POF). Notably, we found that functional FOXL2 is essential for SF-1-...
To present the first case of a patient with oral bisphosphonates-associated ear canal osteonecrosis (BPECO), review previously published cases, and suggest... R Salzman,J Hoza,V Perina,... - Otology & neurotology: official publication of the American Otological Society, American Neurotology Socie...
Here, we report a novel Co3O4-graphene hybrid electrode material with high density Co3O4 nanoparticles (NPs) in a size range of 2-3 nm confined in a few-layered porous graphene nanomesh (PGN) framework driven by an electrochemical process. Raman spectra indicate that Co species preferentiall...
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CAS号[1083-92-7]化源网提供[3-(1,1,1,3,5,5,5-heptamethyl-trisiloxan-3-yl)-4,5-dihydro-3H-pyrazole]MSDS、说明、性质、英文名、生产厂家、作用/用途、分子量、密度、沸点、熔点、结构式等。
an+1 an = n+2 n ,利用“累乘求积”即可得出. 解答:解:(1)∵a1=1,an=3n-1+an-1, ∴an=(an-an-1)+(an-1-an-1)+…+(a2-a1)+a1 =3n-1+3n-2+…+3+1 = 3n-1 3-1 = 1 2 (3n-1). (2)∵a1=4,an+1= n+2 n
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an是正数组成的数列,8Sn=(an+2)的平方.(1)写出数列的前三项(2)求数列的通项公式(3)设bn=4除以(an乘an+1),Tn是数列bn的前n项和,求使Tn小于m除以20对所有正整数都成立的最小正整数
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