An isentropic process is a process in which the entropy remains constant. In this process, the initial (s1) and final (s2) entropies of the system are equal: (7.24)s1=s2 Engineering systems or devices such as pumps, turbines, nozzles, and diffusers essentially operate without exchanging ...
Therefore, the isentropic pressure is always taken to be equal to the actual pressure at the exit of an isentropic process, and the isentropic pressure ratio is always the same as the actual pressure ratio for these systems. The equation for the thermal efficiency of the Carnot cold ASC can ...
Hugoniots for graphite and diamond have been calculated. Numerical simulation data for the graphite–diamond transition in the isentropic compression process using a metallic z -pinch with diamond saving have been reported.doi:10.1134/S1063784217050231V. V. Prut...
When there is no heat transfer occurring between a given system and its environment, a process known as adiabatic takes place. WithQ=0, the first law of thermodynamics reduces to Answer and Explanation:1 Isentropic process is a type of adiabatic process which is reversible. This type of proces...
The correct Answer is:−γ To solve the problem, we need to find the value of b for which the specific heat capacity in the process is zero. We start with the given relationship between pressure p and volume V: p=aVb Step 1: Understand the condition for zero specific heat capacityThe...
In this case, the air is com- pressed to a pressure of 2 bar. The required power for the compressor PC can be determined by Eq. (22), in which C is the isentropic compressor efficiency, cp is the specific heat capacity of air, Π is the total pressure ratio of the compres- ...
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aIn this model, it is assumed that during the vaporization process, only a fraction y of the fluid is transformed into saturated mixture, the other fraction (1-y) remains metastable liquid and is submitted to an isentropic evolution. 在这个模型,它假设,在汽化过程期间,只有流体的分数y被变换成...
Since this is an open system, the energy rate balance for a steady state, steady flow, single-inlet, single-outlet system is (neglecting kinetic and potential energy effects) ERB (SS, SF, SI, SO) Q˙−W˙+m˙m(hm1−hm2)=0and, since an isentropic process is normally also...
and, since an isentropic process is normally also adiabatic, W˙/m˙m=hm1−hm2=cpm(Tm1−Tm2) For an ideal gas in an isentropic process, Eq. (7.38) gives Tm2=Tm1(pm2/pm1)(km−1)/kmand, using the results of Example 12.4, this gives Tm2=(20.0+273.15 K)(1.08/0.101)0.66/...