澳洲AMC数学竞赛2023澳洲AMC真题解析D级 犀牛国际教育独家真题 澳大利亚AMC 最后五题真题及解析D 卷Intermediate Division For questions 26 to 30, colour in the bubbles on the answer sheet to record whole-number answers from 0 to 999. Questions 26 to 30 are worth 6, 7, 8, 9 and 10 marks ...
“我觉得题目很有趣，会让我想要尝试从各种方面思考，用更多方式解决同一道题。”“我感觉AMC使我更善于解决问题了。”每一份Upper Primary的试卷都是30道题，60分钟内完成。题目形式多样，都与日常生活相关，不会有无法理解的题目情景设置。答对得分，错误不扣分。前25题是单项选择题，后5题会要求学生在answer s...
multipliedtimesLaterhefoundthathisanswerislessthanthecorrectanswer.What isthe-digitnumer 一名学生在用66乘如下的循环小数时,其中a和b是数字,他没有 660.5.2 注意到循环小数标识,而只是做了乘。后来他发现他的答案比正确答案小问 位整数是多少? Problem9 Whatistheleastpossilevalueofforrealnumersand? xy 对于实...
instead.Hisanswerwas189largerthanthecorrectanswer. Whatwasthecorrectanswertothemultiplication? 小李尝试将一个一位数乘以36,但他不小心将这个一位数乘以了63。结果比正确结果大189。 这个乘法计算的正确结果是多少? (A)180(B)189(C)216(D)252(E)288 ...
本人又重新试验测试了多次,发现增益应该为4,而不是8,官方datasheet错误了。 下图是实测图之一,VDD2为3.34V,故 计算公式为: VOUT=VOUTP-VOUTN=4*(VINP-VINN)+1.29(由于VDD2不是准确的3.3V,故此处1.29可改为相应实测值,本实验中改为1.30) 这个公式很好的满足了所有试验数据 ...
使用了贵司隔离方法器芯片,型号AMC1301QDWVRQ,对于datasheet推荐电路,如下: 关于采样误差计算,有如下几个疑问请教。 如下如所示的Eg(%)和EG,在计算采样误差时,是两者相加吗? EG: EG(%): 举例:如果R3’=3kΩ,则EG(%)=1-12.5/(12.5+3)=19.35%,如果取EG=0.3%,那么总的放大误差是多少?此时,是采用R3电...
It is your responsibility to correctly code your answer sheet. 7. When your teacher gives the signal, begin working on the problems. THE ANSWER SHEET 1. Use only lead pencil. 2. Record your answers on the reverse of the answer sheet (not on the question paper) by FULLY colouring the ...
5. This is a competition not a test; do not expect to answer all questions. You are only competing against your own year in your own country/Australian state so different years doing the same paper are not compared.6. Read the instructions on the answer sheet carefully. Ensure your name,...
22.Hiram's algebra notes are 50 pages long and are printed on 25 sheets of paper: the first sheet contains pages 1 and 2 the second sheet contains pages 3 and 4. and so on. One day he leaves his notes on the table ...
此外,你表达的意思是不是也间接说明,datasheet中的电机驱动典型应用是错误的?因为上位管导通的时候,必然产生反向电流,进而产生相对GND1的负电压输入到VINP中。 向上0True向下 你表达的意思是不是也间接的说明,datasheet中关于电机驱动的典型应用是错误的?因为上位管导通,必然产生反向电流,进而产生对GND1的负压,并输...