描述下面这段代码完成的逻辑功能。always @ (posedge sys_clk or negedge sys_rst_n) beginif (sys_rst_n == 1'b0)led <= 1'b1;else beginif (switch)led <= 1'b0;elseled <= 1'b1;endend 参考答案:当复位信号为低电平时,led灯点亮。反之,当摁下switch 键,led灯熄灭,不摁下,led灯点亮。
verilog为什么会出现这些警告,//module pll2(clk,rst_b,sysclk);input clk;input rst_b;output sysclk;reg sysclk;reg [2:0] time_cnt;reg [2:0] time_cnt_n;reg inputs_reg1;reg inputs_reg2;always @ (posedge clk) //对输入信号寄存两拍begininpu
同时使用生成和for循环: reg [3:0] temp; genvar i; generate for (i = 0; i < 3 ; i = i + 1) begin: always @(posedge sysclk) begin temp[i] <= 1'b0; end end endgenerate 仅使用for循环: reg [3:0] temp; genvar i; always @(posedge sysclk) begin for (i = 0 浏览7提问于...
(posedge sys_clk or negedge sys_rst_n) begin if (!sys_rst_n) sys_clk_pixel <= 1'b0; else sys_clk_pixel <= ~sys_clk_pixel; end //行坐标和纵坐标 always @ (posedge sys_clk_pixel) begin if (!sys_rst_n) begin x_count <= 0; y_count <= 0; end else if (x_count == ...