Given that alpha,beta,gamma are the zeroes of the polynomial f(x)=x^3-p x^2+q x-r. therefore alpha + beta + gamma = p alpha beta + beta gamma + gamma alpha = q alpha beta gamma = r therefore 1/(alpha beta)+1/(beta gamma)+1/(gamma alpha) =
The potential V(r) shown in Fig. 14(b) for 1≤r/rm≤r0/rm, can be approximated by the polynomial (5.5)V(r)=V0(rrm−1)[5.5187−40.2072(rrm−1)+424.36(rrm−1)2−1690.1348(rrm−1)3+2136.4739(rrm−1)4], where V0=23. We note that, near the maximum. V(r) is...
To solve the problem, we need to find the value of (α+1)(β+1) given that α and β are the zeroes of the polynomial f(x)=x2−p(x+1)−c. 1. Identify the Polynomial: The polynomial is given as: f(x)=x2−p(x+1)−c We can rewrite this as: f(x)=x2−px...
https://www.quora.com/If-alpha-beta-gamma-are-the-roots-of-x-3-x-1-0-then-how-do-I-find-the-equation-with-the-roots-frac-1+-alpha-1-alpha-frac-1-+-beta-1-beta-frac-1+-gamma-1-gamma For cubic polynomial:ax3+bx2+cx+d=0: Sum of roots=−abSum of pairwise products=ac...
Polynomial deceleration for a system of cubic nonlinear Schr"{o}dinger equations in one space dimension In this paper, we consider the initial value problem of a specific system of cubic nonlinear Schrdinger equations. Our aim of this research is to specify t... N Kita,S Masaki,JI Seg...