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知识点4 非线性回归分析将常见的非线性回归模型转化为 ,从而得到相应的回归方程,举例如下:①对 y=a+blnx ,可设 t=lnx ,随后就得到了直线型函数y=a+bt.②对 y=ae^(bx) ,先取对数可得, lny=lna+bx ,然后令 t =lny,这样就得到了直线型函数 t=lna+bx .③对 y=ax^ b ,先取对数可得, lny=lna...
[解答]解:(I) 设函数f(x)=lnx,f(x)的定义域为(0,+∞),因为,所以.当t=e时,lnt=1,即A(e,1),所以切线l的方程为,即 .(II)由(I)知,曲线y=lnx 在点A(t,lnt)处的切线方程为,则,令y=0,得x=t﹣tlnt,所以M(t﹣tlnt,0),,S(t)的定义域为(0,1)∪(1,e)∪(e,+∞).设φ(...
外部播放此歌曲> T-Alnx - 夏天专属的BGM 专辑:A beautiful summer 歌手:T-Alnx 还没有歌词哦
a 为了用数据进行线形最小二乘法的计算,故将x(t)=x0*exp(rt)两边取对数可得lnx(t)=lnx0*exp(rt),lnx(t)=lnx0+rt,另y=lnx(t),a= lnx0,所以可得y= rt+a。 In order to carries on the linear least squares method with the data the computation, therefore nearby two takes x(t)=x0*exp...
已知函数f(x)=alnx-ax-3(x属于R) .(1)求函数f(x)的单调区间;(2)若函数f(x)的图像在点(2,f(2))处的切线的倾斜角为45°,对于任意t属于[1,2] ,函数g(x)=x的三次方+x的平方[f'(x)+m/2]在区间(t,3)上总不是单调函数,求m的取值范围在三角形ABC中,角A,B,C所对应的边分别为a,b,c,...