All numbers divisible by both 3 and 8 are also divisible by which one of the following numbers (A) 5(B) 6(C) 9(D) 21(E) 38 相关知识点: 试题来源: 解析 B The best approach to solving this problem is to find one number that is divisible by both 3 and 8, and then determine ...
must be divisible by all the following numbers except ( ).A. 6 B. 4 C. 2 D. 1 相关知识点: 试题来源: 解析 A A number divisible by 8(such as 8)may not be divisible by 6, but is divisible by 1,2, and 4. 下列哪个数字不能被8整除( ). A.6 B.4 C.2 D.1 可以被8整除的...
Write a C program to calculate the sum of all numbers not divisible by 17 between two given integer numbers. Sample Solution: C Code: #include <stdio.h>intmain(){intx,y,temp,i,sum=0;// Prompt for user inputprintf("\nInput the first integer: ");scanf("%d",&x);...
Here, we are going to implement a Python program that will print all numbers between 1 to 1000, which are divisible by 7 and must not be divisible by 5. By IncludeHelp Last updated : April 13, 2023 Problem StatementGiven a range (which is 1 to 1000) and...
A.telephone numbers B.telephone number C.telephone's number D.telephones numbers 点击查看答案 第7题 All numbers divisible by both 3 and 8 are also divisible by which one of the following num bers? A.5 B.6 C.9 D.21 E.38 点击查看答案 ...
. 由方程组①可得二次方程 2a^2+2ac+2c^2=10a+c , 这样可知c是偶数. 如果c=0,可得解a=b=5,所求的数N为550. 如果c0,那么 2≤c≤8 .由此可得 10a+c≤10a+8 , 2a^2+2ac+2c^2≥2a^2+4a+8 . 由这两个方程得 2a^2+4a+810a+8 . 上式的左端由c=2得到,右端由c=8得到,所以在上式...
12. Find the sum of all the numbers from 1 to 100 that are divisible by 5 but not divisible by 2. 相关知识点: 试题来源: 解析 12.解:1~100的整数中,5的奇数倍数从小到大依次为:5,15,25,35,45,55,65,75,85, 95。 它们的总和是:5 × (1+3+5+⋯+10)=500 。
Each process computes the average of their subset of the numbers. Gather all averages to the root process. The root process then computes the average of these numbers to get the final average. The main part of the code with the MPI calls looks like this: ...
The sum of all the 3-digit numbers, each of which on division by 5 leaves remainder 3 View Solution The sum of all the 3-digit numbers, each of which on division by 5 leaves remainder 3 View Solution Exams IIT JEE NEET UP Board ...
# Python program to multiply all numbers of a list import numpy # Getting list from user myList = [] length = int(input("Enter number of elements: ")) for i in range(0, length): value = int(input()) myList.append(value) # multiplying all numbers of a list productVal = numpy....