All numbers divisible by both 3 and 8 are also divisible by which one of the following numbers (A) 5(B) 6(C) 9(D) 21(E) 38 相关知识点: 试题来源: 解析 B The best approach to solving this problem is to find one number that is divisible by both 3 and 8, and then determine ...
must be divisible by all the following numbers except ( ).A. 6 B. 4 C. 2 D. 1 相关知识点: 试题来源: 解析 A A number divisible by 8(such as 8)may not be divisible by 6, but is divisible by 1,2, and 4. 下列哪个数字不能被8整除( ). A.6 B.4 C.2 D.1 可以被8整除的...
Write a C program to calculate the sum of all numbers not divisible by 17 between two given integer numbers. Sample Solution: C Code: #include <stdio.h>intmain(){intx,y,temp,i,sum=0;// Prompt for user inputprintf("\nInput the first integer: ");scanf("%d",&x);...
Here, we are going to implement a Python program that will print all numbers between 1 to 1000, which are divisible by 7 and must not be divisible by 5. By IncludeHelp Last updated : April 13, 2023 Problem StatementGiven a range (which is 1 to 1000) and...
Step 4: Consider the impact of multiplying by 5 Any number multiplied by 5 will end with a unit digit of either 0 or 5, depending on the other number involved in the multiplication. However, since we are multiplying odd numbers, the unit digit will remain 5. ...
1. Determine all three-digit numbers N having the property that N is divisible by 11, andN/(11)is equal to the sum of the squares of the digits of N.(BGR)1.求出所有的三位数,使得这个三位数除以11所得的商是它各位数字的平方和(保加利亚) ...
0. Donna likes all numbers that are not divisible by3 and Sandra likes all numbers that have no digits divisible by3. How many four-digit numbers are there that both Donna and Sandra like?Donna 喜欢不能被3整除的所有数字,Sandra 喜欢各个数位上的数字都不能被3整除的所有数字。请问有多少个四...
View Solution The sum of all the 3-digit numbers, each of which on division by 5 leaves remainder 3 View Solution The sum of all the 3-digit numbers, each of which on division by 5 leaves remainder 3 View Solution Exams IIT JEE ...
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Question: find all numbers x for which |x−1||x−2|>1. Absolute Value Inequalities Consider an inequality given by an absolute value function,|f(x)|>a. In order to solve this inequality: Solve the inequalityf(x)>awithout the absolute value first ...