1. 理解SQL错误[42601]的含义 SQL错误代码 [42601] 通常表示语法错误。在你提供的情况下,错误消息明确指出“subquery in from must have an alias”,这意味着在FROM子句中的子查询没有分配别名。 2. 识别出导致错误的子查询部分 要解决这个问题,你需要检查你的SQL查询,并找到在FROM子句中没有别名的子查询。例如...
代码语言:sql 复制 SELECT * FROM ( SELECT column1 AS alias_column FROM table_name ) AS subquery_alias WHERE subquery_alias.alias_column = 'some_value'; 以下是使用CTE的示例: 代码语言:sql 复制 WITH cte_alias AS ( SELECT column1 AS alias_column FROM table_name ) SELECT * FROM cte_alias...
Hi, I'm running into the subquery in FROM must have an alias error when generating a sub query and attempting to run it in postgres. (sql/format {:select [:type] :from [[{:select [[:address :field-alias]] :from [:Candidate]} :sub-q-alias...
ERROR: subquery in FROM must have an alias LINE 9: ( ^ HINT: For example, FROM (SELECT ...) [AS] foo. For some SQL pushdown purposes, we are better off generating SQL with the common syntax. I'll file an issue and try to fix it. plan_to_sql(&table_scan_with_projection_alias)...
Error occurs when using table alias in update statement, SQL query update alias is malfunctioning, Table alias causing failure in update query when using correlated subquery, Query with Unclear Table Update
Postgres error: "subquery in FROM must have an alias" StackOverflow: subquery in FROM must have an alias pgsql-hackers: Make subquery alias optional in FROM clause (2017) Bernd Helmle on Twitter Postgres source code: gram.y pgsql-hackers: Making the subquery alias optional in the FROM claus...
This statement is used to specify an alias for a table or the subquery result.table_reference: Can be a table, view, or subquery.As: Is used to connect to table_reference
正确SQL-1 但是如果把 multiIf() 方法放在 ARRAY JOIN之前去判断却是正确的 select DISTINCT `subQuery0`.`yuyi_xxx2` as `column_a`, COUNT(`subQuery0`.`yuyi_xxx1`) as `column_b` from ( select `customer_label.label_id` as `yuyi_xxx1`, multiIf( `t1`. `customer_id` IN ('张三'), ...
@Override public boolean visit(OdpsInsertStatement x) { SQLTableSource from = x.getFrom(); if (x.getFrom() != null) { if (from instanceof SQLSubqueryTableSource) { SQLSelect select = ((SQLSubqueryTableSource) from).getSelect(); print0(ucase ? "FROM (" : "from ("); this.indent...
Describe the bug Alias of a subquery show as a Table node in Visualizes Table/Column Lineage SQL CREATE TABLE main.tab1 AS ( SELECT * FROM ( SELECT T0.* FROM (SELECT * FROM main.tab0) T0 WHERE T0.num < 100 ) ) To Reproduce Note here we r...