To reverse a string A string can be reversed by using stack. The characters of string pushed on to the stack till the end of the string. The characters are popped and displays. Since the end character of string is pushed at the last, it will be printed first. ...
reverse()复杂度O(n) reverse(it1, it2)可以将数组或者容器、字符串在指定范围[it1, it2)内进行反转 #include<iostream> #include<algorithm> using namespace std; int main(){ int arr[10] = {1, 3, 2 ,4 ,7 ,3}; reverse(arr, arr + 5); for(int i = 0; i < 6; i++) { cout...
class Solution { public: typedef struct node { string s; int cnt; }node; static bool cmp(node a, node b) { if (a.cnt == b.cnt) { return a.s < b.s; } return a.cnt > b.cnt; } vector<string> topKFrequent(vector<string>& words, int k) { vector<string> ans(k); map<st...
reverse / reverse_copy / rotate / rotate_copy / search / search_n / set_difference / set_intersection / set_symmetric_difference / set_union / sort / sort_heap / stable_partition / stable_sort / swap / swap_ranges / transform / unique / unique_copy / upper_bound 如果详细叙述每一个...
; using std::endl; using std::get; using std::make_tuple; using std::mt19937; using std::random_device; using std::string; using std::to_string; using std::tuple; using std::vector; using std::uniform_int_distribution; using std::uniform_real_distribution; using std::chrono::...
ra (rotate a) Shift up all elements of stack a by one. The first element becomes the last one. rb (rotate b) Shift up all elements of stack b by one. The first element becomes the last one. rr Perform ra and rb simultaneously. rra (reverse rotate a) Shift down all elements of ...
// alg_equal_range.cpp // compile with: /EHsc #include <vector> #include <algorithm> #include <functional> // greater<int>() #include <iostream> #include <string> using namespace std; template<class T> void dump_vector( const vector<T>& v, pair<typename vector<T>::iterator, typenam...
{protected:usingSet = std::unordered_set<NodeType*>; std::string m_name;public:/*** * Assigns a name to the node. The name is treated as the node ID. * ***/AbstractGraphNode(std::string name) : m_name{name} {}/***
The same method can be used to solve the string concatenation problem above. Assume we have a string of “ABABAB”, then if we get the string that is both prefix and suffix of the original string, and sort them according to the length. we get 1. ABAB 2. AB 3. empty string Then ...
Lab-3: Using L2-level API to implement a single-kernel acceleration for JPEG decoding Lab purpose Operation steps (1) Understand the Work Directory (2) Build kernel for different modes (3) Run kernel in Software-Emulation mode (4) Run kernel in Hardware-Emulation mode (5) Run ...