For a given array, we try to find set of pair which sums up as the given target number. For example, we are given the array and target as: constdata = [2,4,6,10];consttarget =16; We should be able to find 2 pair, which sum up to 16: {2,4,10} {6,10} We need to crea...
This paper presents an algorithm to display squares of 1st N natural numbers without using multiplication (* operator). Instead, the same work can be done using addition (+ operator). The results can also be used to compute the sum of those squares. If we compare the normal method of ...
Following is the algorithm to find all the prime numbers less than or equal to a given integernby Eratosthenes’ method: Create a list of consecutive integers from 2 ton: (2, 3, 4, …,n). Initially, letpequal 2, the first prime number. Starting fromp, count up in increments ofpand...
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fill_n find find_end find_first_of find_if find_if_not for_each for_each_n generate generate_n includes inplace_merge is_heap is_heap_until is_partitioned is_permutation is_sorted is_sorted_until iter_swap lexicographical_compare lower_bound make_heap max...
1577.Number-of-Ways-Where-Square-of-Number-Is-Equal-to-Product-of-Two-Numbers (H-) 1775.Equal-Sum-Arrays-With-Minimum-Number-of-Operations (M+) 1868.Product-of-Two-Run-Length-Encoded-Arrays (M+) 2098.Subsequence-of-Size-K-With-the-Largest-Even-Sum (M+) Binary Search 004.Median-of-...
Instead, we are to find a packing of the n objects into bins of size C using the fewest number of bins. Some fast heuristics that are also ɛ-approximation algorithms are the following: First Fit (FF). Objects are considered for packing in the order 1, 2, … , n. We assume a ...
A simple reduction example is to compute the sum of the elements in an array. float sum_array(float * a, int No_of_elements) { float sum = 0.0f; for (int i = 0; i < No_of_elements; i++) sum + = a[i]; return sum; } With OpenCL, the common way to parallelize a ...
Matrix operator^(const int n){ Matrix ans(I); Matrix temp = *this; int t = n; while(t){ if(t&1) ans=ans*temp; temp=temp*temp; t>>=1; } return ans; } }; int main() { int N; while(scanf("%d",&N) != EOF){ ...
for(int i=0;i<n;i++){ for(int j=0;j<n;j++) scanf("%lld",&A.m[i][j]); } matrix ans=power(); for(int i=0;i<n;i++){ for(int j=0;j<n-1;j++) printf("%lld ",ans.m[i][j]); printf("%lld\n",ans.m[i][n-1]); ...