The first case that you check for in your 'merge step' of the merge sort -- if you have already merged all elements from the list second_half -- has the names of your two lists first_half and second_half switched around. Instead of this: if j >= len(first_half) and i < len(s...
for i in range(len(li)-1): # i表示第几趟 for j in range(len(li)-i-1): # j表示图中的箭头 if li[j] > li[j+1]: li[j], li[j+1] = li[j+1], li[j] ===冒泡排序(优化)=== def bubble_sort_1(li): for i in range(len(li)-1): # i表示第几趟 exchange = False ...
插入排序(英語:Insertion Sort)是一種簡單直觀的排序演算法。 透過構建有序序列,對於未排序資料,在已排序序列中從後向前掃描,找到相應位置並插入。 插入排序在實現上,在從後向前掃描過程中,需要反覆把已排序元素逐步向後挪位,為最新元素提供插入空間。 def insert_sort(nums): for i in range(1, len(nums)):...
j +=1# for k inrange(low, high+1): # li[k] = ltmp[k-low] li[low:high+1] = ltmp defmerge_sort(li, low, high): if low < high: mid = (low + high) //2merge_sort(li, low, mid)merge_sort(li, mid+1, high)merge(li, low, mid, high) # li =list(range(10000)) # ...
常用algorithm及其Python实现 常⽤algorithm及其Python实现冒泡排序 def bubble_sort(li):for i in range(len(li)-1): # i表⽰第⼏趟 for j in range(len(li)-i-1): # j表⽰图中的箭头 if li[j] > li[j+1]:li[j], li[j+1] = li[j+1], li[j]===冒泡排序(优化)=== def bubb...
希尔排序(Python实现) 摘要:[TOC] 1.for版本 希尔排序 python def shell_sort_for(a_list): '''希尔排序for版本''' num = len(a_list) gap = num // 2 for k in range(gap, 0, gap//2): while gap 0: fo 阅读全文 posted @ 2019-01-20 22:23 zkeeper 阅读(180) 评论(0) 推荐(0)...
Post Your Answer By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy. Not the answer you're looking for? Browse other questions tagged algorithm sorting python-3.x time-complexity mergesort or ask your own question. The...
Python 版本 21.合并两个链表 将两个有序链表合并为一个新的有序链表并返回 算法思想:按部就班写吧? C++版本 struct ListNode{ int val; ListNode* next; }; ListNode *merge2node(ListNode *head1, ListNode *head2){ if(head1==NULL||head2==NULL) { ...
python 实现代码如下: process:增量的存在是将index相差增量的分到一组 比如arr:5,7,8,3,1,2,4,6 [index: 0,1,2,3,4,5,6,7] length = 8, 这个的gap = 4, 此时a[0],a[4]一组,a[1],a[5]一组,...每个组进行insertion sort for i in range(gap, n) - for i in range(4, 8):...
for (i = s; i <= e; i++) { /* Copy data to temp array to our array */ arr[i] = temp[i]; } } void mergeSort(vector<int> &arr, int s, int e) { if (s >= e) { return; } // Same as (s+e)/2 int mid = s + (e - s) / 2; mergeSort(arr, s, mid); ...