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\(\begin{array}{l}1+ \bar{B} = 1\end{array} \) Therefore, \(\begin{array}{l}C+\bar{BC} = 1\end{array} \) Question 2: Draw a truth table for A(B+D). Solution: Given expression A(B+D). ABDB+DA(B+D) 00000 00110 ...
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15-12-20161/2Algebra2Unit02LessonAnswersAlgebra2Unit02LessonAnswersbyTimSchmitzClickhereforFreeRegistrationofAlgebra2Unit02LessonAnswersBookRatedfrom104votesBookID:781F3B726D82922FCE3E9B01B5835FCBDateofpublishing:December8th,2016Numberofpages:340pagesThankyoufordownloadingalgebra2unit02lessonanswers.Maybeyou...