意外发现测量两个2.2M电阻中间电压时能够启动电源输出，并且后来开关几次都能正常工作，思来想去也就...
ADP-90cb db 是台达代工制造 pa-1900-24 是光宝代工制造
AC Adapter Charger for Asus ADP-65GD B, ADP-65JH AB, ADP-65JH BB; Asus ADP-65JH CB, ADP-65JH DB, ADP-75SB BB; Asus ADP-90CD BB, EXA0703YH, EXA1203YH $1699 current price $16.99 AC Adapter Charger for Asus ADP-65GD B, ADP-65JH AB, ADP-65JH BB; Asus ADP-65JH CB, ADP-65...
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¥[1_7ij1w4tp#51#MzMzMz5tWWXQbz1lT2RzbkdjlmgCb3ZhyWLzbmZjPmsrY2dqZGQKZe5t1FKNbdpr+Wu1YW9r/nyXY5NhC1OQbs9ollErYclgdG9Ca9Ni+mwKbNNsUGk9YFhi3GrJU+hgv30n] 原装三星显示器S24E390HL S27E360H S27E390H充电源适配变压器线 ¥[1_7ij1w4tp#51#UVFRUVwBOg0kApEw3g0ZCBEw3g7BA1AfAg...
(1)证明:四边形ABCD是矩形,AD =BC,∠D = ∠BCD =90°.又∵∠APB=90° ∴∠DAP+∠APD= 90° ,∠APD + ∠BPC=90° , ∴∠DAP=∠BPC 又∵∠D=∠BCP=90° ,∴△ADP\backsim△PCB∴(AD)/(PC)= (DP)/(CB) ∵AD=BC , ∴(AD)/(PC)=(DP)/(AD), ∴AD^2=DP⋅PC (2)解:四边...
【题目】如图1,在矩形ABCD中,P为CD边上一点(DP<CP),∠APB=90°.将△ADP沿AP翻折得到△AD′P,PD′的延长线交边AB于点M,过点B作BN∥MP交DC于点N. (1)求证:AD2=DPPC; (2)请判断四边形PMBN的形状,并说明理由; (3)如图2,连接AC,分别交PM,PB于点E,F.若=,求的值....
∵PQ⊥CB,∴∠AWD=∠PQD=90°,∴∠WAD+∠ADW=90°,∵∠ADP=90°,∴∠ADW+∠PDQ=90°,∴∠DAW=∠PDQ,∵AD=DP,∴△ADW≌△DPQ(AAS),∴AW=DQ,DW=PQ,∵AB=AC,∠BAC=90°,∴BW=CW,∴AW=CW=12BC,∴CW=DQ,∴CQ=DW,∴CQ=PQ=2;(3)如图2,AF=2PE,理由如下:作PV⊥BC于V,作AW⊥BC于W,作...
,从而可求出EF=AF﹣AE AC AC,代入即可得出结论. (1)∵ABCD是矩形,∴AD=BC,∠D=∠C=90°,∴∠DPA+∠DAP=90°. ∵∠APB=90°,∴∠DPA+∠CPB=90°,∴∠DAP=∠CPB,∴△ADP∽△PCB,∴ . ∵AD=CB=2,∴ ,∴PC=4; (2)∵DP∥AB,∴∠DPA=∠PAM,由题意可知:∠DPA=∠APM,∴∠PAM=∠APM. ...
原装华硕Y4000U Y4200F Y5000U Y5200F笔记本电脑充电源适配器线 ¥[1_7ij1w4tp#51#Ly8vLyJwcHSqT5Z3F2FJfrVh0HeBdJlz3mAgcuF7lXx9dvh3U3Mddk9/VHZ+esVPF3fPc2BPn3N4cyV++3W2cCdxAA==] 机械革命S1 Pro-02 S1-01 02 03笔记本电源适配器变压器充电器线 ¥[1_7ij1w4tp#51#UlJSUl8LGA9JHPgGK...