1443:【例题4】Addition Chains题解注释在代码里注意优化搜索顺序以及最优化剪枝代码#include<iostream> #include<cstdio> #include<algorithm> #include<cmath> #include<cstring> #include<string> #include<queue> #include<functional> using namespace std; int n,minn,ans[2019],a[2019]; //n是序列的最大...
1443：【例题4】AdditionChains 题解 注释在代码⾥ 注意优化搜索顺序以及最优化剪枝 代码 #include<iostream> #include<cstdio> #include<algorithm> #include<cmath> #include<cstring> #include<string> #include<queue> #include<functional> using namespace std;int n,minn,ans[2019],a[2019];//n是序列...
由于要记录路径,不能用循环队列,就必把数组开的足够大,开始开到10000,re了,加了个0,就过了。 #include <iostream> #include <cstring> #include <queue> #include <string> #include <cstdio> usingnamespacestd; intn; structnode { intid; intval; intpre; node(){} node(inti,intv,intp):id(i),...
POJ-2248 二.题目大意: 序列x 有如下性质: ① x[1] = 1 ② x[m] = n ③ x[1] < x[2] < ... < x[m - 1] < x[m] ④ 对于每个 k (2 ≤ k ≤ m),都存在 两个整数 i,j (1 ≤ i,j ≤ k - 1),使得 x[k] = x[i] + x[j]. 题目给出 n,要求构造出序列 x. 三.分...
POJ 2248 - Addition Chains - [迭代加深DFS] http://bailian.openjudge.cn/practice/2248 题解: 迭代加深DFS。 DFS思路:从目前 $x[1 \sim p]$ 中选取两个,作为一个新的值尝试放入 $x[p+1]$。 迭代加深思路:设定一个深度限制,一旦到达这个界限,即继续往下搜索;该深度限制从 $1$ 开始,...
The computational generation of minimal-length addition chains over the last sixty years or so has yielded many new results concerning addition chains. The computer search for such chains often involves a search tree which is traversed to produce addition chains. A depth first search of the search...
1.Fast and secure elliptic curve scalar multiplication algorithm based on special addition chains;基于特殊加法链的快速安全椭圆曲线标量乘算法(英文) 4)Machining Methods加工方法链 英文短句/例句 1.Decision of Alternative Process Links with Constraint Condition Based on T_invariant of Petri Nets基于Petri网T...
#include <cmath> #include <deque> #include <vector> #include <queue> #include <string> #include <cstring> #include #include <stack> #include <set> //吐槽一下poj,万能头不给过 *^* using namespace std; int n,sp,a[10000001]; bool dfs...
UVA529 Addition Chains 题意: 一个与 nn 有关的整数加成序列 $$ 满足以下四个条件: 1.$a_0=1$ 2.$a_m=n$ 3.$a_0<a_1<a_2<...<a_{m-1}<a_m$ 4. 对于每一个 k(1≤k≤m) 都存在有两个整数 i 和 j(0≤i,j≤k-1,i和 j 可以相等 ) ,使得 $a_k=a_i+a_j$ 你的任...
代码: #include <algorithm> #include <iostream> #include <cstring> #include <string> #include <vector> #include <cstdio> #include <stack> #include <list> using namespace std; #define MAXN 10005 int n , Min; int ans[MAXN] , temp[MAXN];//ans存储最后的结果,temp存储每一个状态 ...