package chapter_2_listproblem;import java.util.Stack;publicclassProblem_10_AddTwoLinkedLists{publicstaticclassNode{publicintvalue;publicNodenext;publicNode(intdata){this.value=data;}}publicstaticNodeaddLists1(Nodehead1,Nodehead2){Stack<Integer>s1=newStack<Integer>();Stack<Integer>s2=newStack<Integer...
(dummy其实只是一个node,然后把计算得到的node依次在其后记录,最终的dummy.next其实也是一个node) 代码: defaddTwoNumbers(self,l1,l2):""" :type l1: ListNode :type l2: ListNode :rtype: ListNode """curr=dummy=ListNode(0)left=0whilel1orl2orleft:(l1,num1)=(l1.next,l1.val)ifl1else(None,0)...
首先第一种方法 两个单个节点还有进位相加实现如下: 1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) { val = x; }7* }8*/9publicclassSolution {10publicListNode addTwoNumbers(ListNode l1, ListNode l2) {11if(l1==null&&...
LinkedList<Integer> list3 =newLinkedList<Integer>();intsum = 0;while(!list1.isEmpty() || !list2.isEmpty() || sum != 0) {inttempsum =sum;if(!list1.isEmpty()) { tempsum+=list1.poll(); }if(!list2.isEmpty()) { tempsum+=list2.poll(); } list3.addFirst(tempsum% 10); ...
Add Two Numbers 描述 You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
这两个数342和465之和就是807。 807应该是按照7 -> 0 -> 8的形式存储在返回的linked list里的。 所以,在python中执行这个操作就是: class ListNode: def __init__(self, val=0, next=None): self.val = val self.next = next def addTwoNumbers(l1, l2): ...
3 输入与输出：/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { }};4 解决思路：从表头开始相加，记录每次相加...
# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: link1 = l1 ...
2. Add Two Numbers(链表尾插法) You are given twonon-emptylinked lists representing two non-negative integers. The digits are stored inreverse orderand each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
Each node of linked list is represented by single digit and head node is most significant digit. For example: Sum of two number: 56712 + 6359———– 63071 So it will be represented in below format as linked list: Algorithm: Create two linkedlist which will represent above two numbers. ...