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Absolute Max/Min of y = x^2 * e^-x on [-1,3] Homework Statement Find the absolute max/min on [-1,3] for y = x^2 * e^-x Homework Equations The Attempt at a Solution F'(y) = (2x)(e^-x) + (x^2)(e^-x) = xe^-x(2 + x) x = 0, -2 (Critical Points) F(-...
this.MinValue = min; this.MaxValue = max; this.MeanValue = sum/Count; // second pass for variance double var = 0, dev = 0, dx; for (int i = 0; i < data.Length; i++) { dx = data[i]-MeanValue; dev += Math.Abs(dx); var...
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lessThan(resourceCalculator, csContext.getClusterResource(), queueUsage.getUsed(nodePartition), queueResourceQuotas.getEffectiveMinResource(nodePartition))); return; } float usedCapacity = queueCapacities.getAbsoluteUsedCapacity(nodePartition); float guaranteedCapacity = queueCapacities.getAbsoluteCapacity(...
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MHBFind Min/Max of f: 2cos(x)+sin(2x) & x^2+16/x 4)Find the absolute minimum and absolute maximum values of f on the given interval. a) f(x) = 2cos (x) + sin (2x) on [0, π/2] b) f(x) = x^2 +16/x on [1, 3] Thanks again in advance!