ABC is a triangle right angled at Aand a perpendicular AD is drawn on the hypotenuse BC. What is BC.AD equal to ? AAB .AC BAB . AD CCA .CD DAD . DBSubmit Question 3 - Select One ΔABC has a right angle at A. If BC = √2andAB=AC=1, then sin B is equal to A1√2 B...
In figure, ABC is a right triangle, right angled at B. AD and CE are the two medians drawn from A and C respectively. If AC = 5 cm and AD=(3sqrt5)/(2)cm, find
5.ABC is a triangle right-angled at A,and D is the foot of the altitude from A.The straightline joining the incenters of the triangles ABD,ACD intersects the sides AB,AC at thepoints K,L respectively.S and T denote the areas of the triangles ABC and AKL respective-ly.Show that S2T...
28In the figure below, ABC is a right-angled triangle. EF is parallel to GH.Find ∠BCH.E77°50°B GC H∠ACB =180°-90°-50°=40°∠ACH =77°∠BCH =77°-40°=37°37ūAns:O 相关知识点: 试题来源: 解析 ∠ACB=180°-90°-50°=40° ∠ACH=77° ∠BCH=77°-40°=37°37 ...
9 In the figure below, ABC is a right-angled triangle. BCD and BFE are straight lines. ZBAF is 27. ∠AFB is 77° and ZEDB is 84°.Find ∠BED.A E77°F84%B CD 相关知识点: 试题来源: 解析 ∠ABF=180-77-27°=76°∠EBD=90°-76°=14°∠BED=180°-14°-84°=82° ...
1.ΔABC is a right-angled triangle with∠BAC=90°.AF is perpendicular to BC.D is a point on ACsuch that BD=DC=FC=1.what is the length of AC.2.InΔABC,∠ACB=120°.CH perpendicular AB.GIVEN THAT CA+AH=HB.FIND∠B3.AREA OF ΔABK=6,BD:DC=3:5 AND AK;KD=4;5.FIND THE ...
百度试题 结果1 题目 ABC is a right angled triangle A50cm AB =50cm and ACB =16°Find AC16°(50)/(sin16)=181.4cm 相关知识点: 试题来源: 解析 ==181.4cm 反馈 收藏
Triangle (ABC) is a right angled triangle. Also (AC=5), (CB=3) and angle (ADB) is a right angle.What is the length of (DB)? 相关知识点: 试题来源: 解析 (2.4) This is another special triangle problem. The hypotenuse =5, one leg =3, so the other leg ((AB)) =4Now ...
is a right-angled triangle and ∠ABC=90∘, if the distance from B to the mid-point of AC is 6cm, find the maximum value of the area of △ABC. 已知△ABC是一个直角三角形且∠ABC=90∘,若B点与AC的中点的距离为6厘米,求△ABC的面积的最大值.相关...
ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (i) D is the mid-point of AC (ii) MD⊥AC (iii) CM=AM=12AB View Solution Q3 ABC is a triangle right angled at C. A lin...