A particle P, moving in a straight line, passes through a fixed point O at time t=0 s. At time t s after leaving O, the displacement of the particle is x m and its velocity is v ms-1, where v=12e^(2t)-48t, t≥ 0.
A particle moying in a straight line passes through a fixed point 0. The displacement, x metres, of the particle, t seconds after it passes through O, is given by$$ x = 5 t - 3 \cos 2 t + 3 $$(i) Find expressions for the velocity and acceleration of the particle after i seco...
On a sphere that passes through Formula Not Shown lattice pointsNo AbstractMaehara, H.EUROPEAN JOURNAL OF COMBINATORICS
Determine the point P where the line x = 1 + t, y = 2t, z = -3t intersects the plane x + y - z = -3. Determine the point P where the line x = 1 + t, y = 2t, z = -3t intersects the plane x +...
2023年顺德区中职学校一年级《英语》期末统测试题(A)本试卷共10页,85小题,满分 100 分。考试用时 90 分钟。注意事项:1.答卷前,考生务必用黑色字迹的钢笔或签字笔将自己的学校、班级、姓名、学号填写在答题卷上。2.选择题每小题选出答案后,用2B铅笔把答题卷上对应题目选项的答案信息点涂黑,如需改动,用橡皮擦...
19 A particle is moving in a straight line which passes through a fixed point O.The displacement, s metres, of the particle from O at time t seconds is given by$$ s = 1 0 + 9 t ^ { 2 } - t ^ { 3 } $$(a) Find an expression for the velocity, v m/s, of the particle...
12 A particle moves in a straight line and passes through a fixed point O. The velocity of the particle, v ms', is given by v=-t^2+2t+8 where / is the time, in s, after leaving O.[Assume motion to the right is positive.]Find(a) the initial velocity, in ms', of the parti...
Let the required equation in intercept form be \frac{x}{a}+\frac{y}{b}=1 Therefore, its x- intercept is a and y- intercept is b \implies A(a,0) and B(0,b) is on the given line. And it is given the point (3,-2) divides the line segment A(a,0) and B(0,b
When X=mg, the partial P is in equilibrium and on the point of sliding down the plane. Show that u=(k tan a−1)/ k + tana Deduce that, when k =1 ,a must be greater than 45 这是一道很经典的受力分析的题,同学们要先对particle P进行受力分析,rough plane,particle slide down的趋...
A plane passes through the point (1,-2,3) and is parallel to the plane 2x-2y+z=0. The distance of the point (-1,2,0) from the plane, is