A particle moves along x-axis as x=t(t−2)+(t−2)2 . Which of the following is true? AThe initial velocity of particle is 4 BThe accekeration of particle varies with time CThe particle is at origin at t = 0 DNone of theseSubmit A particle moves along the X-axis as x=u...
A particle moves along the X-axis. Its X-coordinate varies with time according to the expressionx=4t+2r2,where x is in meters and t is in seconds. The position-time graph for this motion is shown in the figures previously. Note that the particle moves in the negative X-direction for ...
A particle moves along the x-axis so that at any time t≥q 0, its position is given by x(t)=(sin (3t))^2 . What is the speed of the particle at t= (π )4? ( ) A. -3 B. -1 C. 1 D. 3 相关知识点: 试题来源: ...
Using x(t)=8t^( 5/2)+Ct+16 and the position of the particle at t=1 allows you to solve for C. The position at t=1 was given as 9. When you substitute t=1 and x(t)=9 into the position function, the constant C equals -15. The question is asking for v(0). Because ...
To find when the particle is at rest, you must set thev elocity function equal to 0 and solve for t. The velocity function is the first derivative of the position function. Remember to use the product rule on the position function in order to take the derivative correctly.x(t)=te^(...
题目A particle moves along the x-axis so that at any time t≥q 0 the acceleration of the particle is a(t)=e^(-2t). If at t=0 the velocity of the particle is 52 and its position is (17)4, then its position at any time t>0 is x(t)= ...
A particle moves along the x-axis in such a way that its acceleration at time t for t≥q 0 is given by a(t)=4cos (2t). At time t=0, the velocity of the particle is v(0)=1 and its position is x(0)=0.Write an equation for the velocity v(t) of the particle. 相关知识点...
5. A particle moves along the x-axis. At time t seconds, t 0, the velocity of the particle is3/2vms-1 in the direction of x increasing, where v = 2t- 6t + 2At time t= 0 the particle passes through the origin O. At the instant when the acceleration of the particle is z...
A particle moves along the x-axis at a velocity of v(t)= 1(√ t), for t>0. At time t=1
A particle moves along the x-axis with its velocity at time t given by v(t)=bt^2-ct+8, where b and c are constants and b does not equal c. For which of the following values of t is the particle at constant velocity?( ) A. t= c(2b) B. t=2bc C. t= (2b)c D. t=2b...