A particle is projected from ground with initial velocityat. Find (a) R,H and T, (b) velocity of particle after 1 s (c) velocity of particle at the time of collision with the ground (x-axis). View Solution A pa
【题目】 A particle is projected from a point o, with a n initial velocity of u m $$ s ^ { - 1 } $$,at an angle of a to the horizontal. In the vertical plane of proj ection, taking and y as the horizontal and v ertical aces respectively Given that u=42 and t hat the ...
A particle is projected form a horizontal plane (x-z plane) such that its velocity vector at time t is gives by vecV = ahati +(b - ct)hatj. Its range on the h
【题目】 A particle is projected from a point o, with an initial velocity of u m s-1, at an angle of ato the horizontal. In the vertical plane of projection, taking and y as the horizontal and vertical axes respectively Given that u=42 and that the particle passes through the point ...
Give non-exact numerical answers correct to3significantfigures,or1decimal place in the case of angles in degrees,unless a different level of accuracy is specified in the question.Where a numerical value is necessary,take the acceleration due to gravity to be10m s−2.At the end of ...
e,f, Measured transmission spectrum (e) and calculated projected band (f) when the device works at θ = 0.08π. There are five bulk bands in one FSR, distinct from the three-particle model in a square lattice. The winding numbers \({{{\mathcal{W}}}\) in all bulk bandgaps are...
8. A particle is projected from a point O with speed u at an angle of elevation a above the horizontal and moves freely under gravity. When the particle has moved a horizontal distance x, its height above O is y.(a) Show that y=xtanα-(gx^2)/(2u^2cos^2α)(4) A girl throw...
Dparticle is at height of60mfrom ground Submit A ball is projected vertically upward with a velocity112m/sThe time taken by it to return to the point of projection is (g=10m/s2) : View Solution Free Ncert Solutions English Medium
A particle is projected with speed 15ms^-1 at an angle of 40" above the horizontal from a point on horizontal ground. Calculate the time taken for the particle to hit the ground. 相关知识点: 试题来源: 解析 1.93$$ 0=(15 \sin 40^{\circ})t-gt^{2}/2 \\ t=1.93 $$ ...
85 mA particle is projected vertically upwards from the top of tower with velocity 10 m/s. It reaches the ground in 5 s. find Average speed & average velocity of particle.