A ball of mass M moving with velocity V0 on a frictionless plane strikes the first of two identical balls, each of mass m=2kg, connected by a massless spring with spring constant k=1kg/s2(see Figure). Consider the collision to be central and elastic and essentially instantaneous.Mkmm00000...
题目【题目】A ball of mass m is thrown with initial velocity u and experiences a resist-ance to motion of m |v where v is the velocity at any instant of time t.Fn ifrnilquogvng ntrmovangHence find an expression for T, the time taken to reach maximum height. 相关知识点: ...
7 (a) A ball is kicked from point A, 1.0 m above the ground with a velocity of 20.0 m s1 at an angle 50° to the horizontal as shown in Fig. 7.1. It reaches the maximum height at point H and finally lands on the ground at B. Assume air resistance is negligible.H20.0 ms-150...
A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 m s−1 .Calculate the maximum potential energy it gains as it goes up. View Solution A cricket ball of mass 100 g moving with a speed of 30ms−1 is brought to rest by a player in 0.03 s. Find...
How high will it go? (Ignore air resistance) A. 10 m B. 20 m C. 30 m D. 40 m 相关知识点: 试题来源: 解析 B。根据竖直上抛运动的公式 h = v₀²/2g ,代入数据可得 h = 20²/(2×10) = 20 m 。选项 A、C、D 均是计算错误。反馈 收藏 ...
A golf ball is hit with an initial velocity of 130 feet per second at an inclination of 45° to the horizontal. In physics, it is established that the height h of the golf ball is given by the functionh(x)=(-32x^2)(130^2)+x...
1. A ball is thrown directly upwards with an initial velocity of 20m/s. Determine the ball’s maximum height and the time it will take for the ball to fall from its maximum height to the ground. (10 marks) h=1/2*m*v^2/(mg)=20 m (here, v^2 stands for v², g=10 m/s^...
1.A ball is thrown directly upwardswith an initial velocity of 20m/s.Determine the ball’s maximum height and thetime it will take for the ball to fall from its maximum height to the ground.(10 marks)2.A man hauls a 20kg stone thatis currently resti
A ball is thrown upward with an initial velocity of 15.5m/s.For how long is the ball higher than 10.5 meters?是AL MATHS MECHANICS1上的.第82页的10题 答案 这题问的是小球高度大于10.5米的持续时间.列出重力加速度方程得15.5t-1/2gt²=10.5 其中g=10解得t=1s或 t=2.1s故,持续时间为2.1-1...
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