直接用数组模拟加法即可，希望能够帮助到你 include<stdio.h> include<string.h> void main(){ char a[1000],b[1000];int T,i,j,la,lb,max;scanf("%d",&T);getchar();for(i=1;i<=T;i++){ int c[1001]={0},a1[1000]={0},b1[1000]={0};scanf("%s",a);scanf("%s",b)...
40if(i>=mll&&a2.length()>a1.length()){41arr4[i]=(((int)arr3[i]-48)+flag)%10;42flag=(((int)arr3[i]-48)+flag)/10;43}44if(i==ml-1&&flag==1){//确定最高位是否为进位得到的145arr4[i+1]=1;46}4748}495051if(arr4[ml]==0){//最高位为0则不输出最高位,52reverse(arr4...
A + B Problem II(大数加法) 一直格式错误,不想改了,没A 1#include <iostream>2#include <stdio.h>3#include <string.h>4#include <stdlib.h>5usingnamespacestd;67intmain()8{9intT,K=0;10scanf("%d",&T);11chara[1002],b[1002];12intta[1002],tb[1002];13getchar();14while(T--)15{16...
A+B Problem (II) : Input/Output Pratice Time Limit: 1 Sec Memory Limit: 2 MBSubmit: 571 Solved: 431[Submit][Status][Web Board]Description 计算a+b，0<=a,b<1000。Input 输入的第一行是一个整数N，后面有N对整数a和b，每对a和b占一行，a,b用空格分开。Output 每行输出一个a+...
include<stdio.h> include<stdlib.h> int main(){ int a,b;while(scanf("%d%d",&a,&b)!=EOF)printf("%d\n",a+b);system("pause");return 0;} 应该是正确的。。。
将第一个for(;i>=0,j>=0;)改为for（；i>=0&&j>=0;)
int main(){ int t,i,len_str1,len_str2,len_max,k,num=1;char str1[1000];char str2[1000];scanf("%d",&t);getchar();while(t--){ int a[1000]={0},b[1000]={0},c[1001]={0};scanf("%s",str1);len_str1=strlen(str1);for( i=0;i<=len_str1-1;++i){ a[i...
2)A + B = SUM 之后要换行 方法一: #include<stdio.h>#include<string.h>voidReverse(char*,int);intmain(void){chara[1003]={0};charb[1003]={0};charc[1003]={0};intn=0;intl=0;intla=0;intlb=0;intx=0;intnum=1;intzeroid[2]={0};scanf("%d",&n);for(inti=0;i<n;i++){ze...
Problem Description Ihave a very simple problemforyou.Giventwo integersAand B,your jobisto calculate theSumof A+B. Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, ...
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