【解析】答案:12.解:由 a^2+b^2+c^2=ab+bc+ 得2a^2+2b^2+2c^2-2ab-2bc-2ac=0 由完全平方公式,得(a-b)^2+(b-c)^2+(a-c)^2=0 由( a-b)^20,(b-c)^20,(c∈ a-c)2得a=b=c结合已知条件a+2b+3c=12,得a=b=c=2所以a^2+b^2+c^2=12【完全平方公式的推导】...
2【题目】如果a+2b+3c=12,且 a^2+b^2+c^2=ab+bc+ca,则 a+b^2+c^3 等于()。A.12B.14C.16D.18 3【题目】如果a+2b+3c=12,且a2+b2+c2=ab+bc+ca,则a+b2+b3的值是().A.12B.14C.16D.18 4【题目】如果a+2b+3c=12,且a2+b2+c2=ab+bc+ca,则a+b2+c3等于()。A.1...
因为a^2+b^2+c^2=ab+ac+bc,所以(a-b)^2+(b-c)^2+(c-a)^2=0,所以a=b=c 所以a=b=c=2,所以a+b^2+c^3=2+4+8=14 注：a^2相当于a的2次方
分析：首先将a2+b2+c2=ab+ac+bc式子左右两边同乘以2，移项、拆分项、利用完全平方式转化为（a-b）2+（a-c）2+（b-c）2=0．再根据非负数的性质得出a=b=c的关系．再结合a+2b+3c=12，求得a、b、c的值．最后将a、b、c的值代入a+b2+c3求得结果．解答：解：∵a2+b2+c2=ab+ac+bc，...
2B. DEGs in MF were significantly enriched in the categories ‘ion channel activity’, ‘ligand-gated cation channel activity’, ‘calcium channel activity’, ‘voltage-gated cation channel activity’ and ‘cation channel activity’. The bar graph is shown in Fig. 2C. Table 3 enlists the ...
2b). Notably, molecular phenotypes exhibited a high proportion (an average of 70%) of their own specific molQTL after taking linkage disequilibrium (LD) between SNPs into account (Fig. 2b), indicative of their distinct underlying genetic regulation. On average, 20% of eGenes, 13.5% of s...
2B. c RNA-ISH validation in 3D epithelium for C9 biomarkers shows many cells with multiple puncta in HPV16+ epithelium, primarily in superficial suprabasal layers, vs very few in HPV16− epithelium. Scale bar, 25 µm. Arrows highlight positive staining in cells. d Quantification of ...
a+2b=3c，abc分别是：a=3c-2b b=（3c-a）/2 c=（a+2b）/3
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