int rsum=MaxSubeqSum3(a,middle+1,right);//递归寻找两边子序列最大和/* 再分别找左右跨界最大子列和*/int leftmaxsum = 0;int leftthissum = 0;for(int i=middle;i>=left;i--){ //应该从边界出发向左边找leftthissum += a[i]; if(leftmaxsum < leftthissum) leftmaxsum = leftthissu...
7-1 Maximum Subsequence Sum (25分) 解题思路:寻找最大子列和,并输出最大子列和的第一个数和最后一个数 #include <stdio.h>intmain(intargc,char**agrv) {intn;inti; scanf("%d",&n);inta[n];intb[2];intsum=0;intmax=0;intcnt=0,count=0,tmp=0;for(i=0; i<n; i++) { scanf("%d...
#include<iostream> using namespace std; int main() { int n,m=-1,b=0; scanf("%d",&n); int a[n],s=0,e=0,l,r; for(int i=0; i<n; i++) { cin>>a[i]; b+=a[i]; e=i; if(b>m) { m=b;//更新最值以及起终点 l=s; r=e; } if(b<0) { b=0;//重置起点 s=...
Ni+1, ...,Nj } where1. The Maximum Subsequence is the continuous subsequence which has the largest sum of its elements. For example, given sequence { -2, 11, -4, 13, -5, -2 }, its maximum subsequence
PAT | A1007 Maximum Subsequence Sum(25')【动态规划】 动态规划 专题 PAT A1007 Maximum Subsequence Sum (25’) 题目 思路 三种情况 最大连续子序列和唯一:输出最大值,以及首尾两个元素 最大连续子序列和不唯一:输出最大值,以及最小的首尾两个元素 最大连续子序列每个元素都是负数:输出 0,以及首尾两个元...
0392-is-subsequence.py 0394-decode-string.py 0410-split-array-largest-sum.py 0416-partition-equal-subset-sum.py 0417-pacific-atlantic-water-flow.py 0424-longest-repeating-character-replacement.py 0435-non-overlapping-intervals.py 0438-find-all-anagrams-in-a-string.py 0...
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697. Degree of an Array # 题目 # Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarra
The best way is to split it into[7,2,5]and[10,8], where the largest sum among the two subarrays is only 18. Analysis: 这道题有DP和binary search两种做法。DP的话实现起来稍微麻烦一点,需要保存一个2d的array,大小为n*m,每个位置(i,j)保存从数列位置i开始到数列尾端,分割成j份的largest sum...