因式分解:3x2+4xy-y2. 相关知识点: 试题来源: 解析 解:3x2+4xy-y2=3(x2+4/3xy-1/3y2)=3[(x2+2×2/3xy+4/9y2)-1/3y2-4/9y2]=3[(x+2/3y)2-7/9y2]=3(x+2/3y+(√7)/3y)(x+2/3y-(√7)/3y)=3[x+(2+√7)/3y)(x-(2-√7)/3y). 首先提取公因式3,再利用配方法把...
分析首先提取公因式3,再利用配方法把式子变形,然后利用完全平方公式进行分解,再利用平方差公式进行三次分解即可. 解答解:3x2+4xy-y2=3(x2+xy-y2)=3[(x2+2×xy+y2)-y2-y2]=3[(x+y)2-y2]=3(x+y+y)(x+y-y)=3[x+y)(x-y). 点评此题主要考查了因式分解,关键是掌握分解因式的方法,先提...
分析:首先提取公因式3,再利用配方法把式子变形为3[(x2+2× 2 3 xy+ 4 9 y2)- 1 3 y2- 4 9 y2],然后利用完全平方公式进行分解,再利用平方差公式进行三次分解即可. 解答:解:3x2+4xy-y2 =3(x2+ 4 3 xy- 1 3 y2) =3[(x2+2× ...
y,x2= −2− 7 3y,故原式=3x2+4xy-y2=3(x- −2+ 7 3y)(x- −2− 7 3y). 首先求出3x2+4xy-y2=0的根,进而分解因式得出即可. 本题考点:实数范围内分解因式. 考点点评:此题主要考查了实属范围内分解因式,求出方程的根是解题关键. 解析看不懂?免费查看同类题视频解析查看解答...
3x2+4xy-y2 =3x²-(y²-4xy)=3x²-(y²-4xy+4x²)+4x²=7x²-(y-2x)²=(√7x+y-2x)(√7x-y+2x)=[(√7-2)x+y][(√7+2)x-y]
【解析】3x^2+4xy-y^2 =3(x^2+4/3xy-1/3y^2) =3((x^2+2*2/3xy+4/9y^2)-1/3y^2-4/9y^2 =3((x+2/3y)^2-7/9y^2) =3(x+2/3y+2/3y)(x+2/3)-(2/7)/x=(2-√7)/1 =3(x+(2+√7)/3y)(x-(2-√7)/3y)故答案为:3(x+(2+√7)/3y)(x-(2-√7)/3y)【提...
分析: 首先求出3x 2 +4xy-y 2 =0的根,进而分解因式得出即可. 解答: 解:当3x 2 +4xy-y 2 =0, 解得:x 1 = -2+ 7 3 y,x 2 = -2- 7 3 y, 故原式=3x 2 +4xy-y 2 =3(x- -2+ 7 3 y)(x- -2- 7 3 y). 点评: 此题主要考查了实属范围内分解因式,求出方程的根是解...
3x2+4xy-y2因式分解 3x²+4xy-y²因式分解 3x²+4xy-y²=3(x²+4xy/3)-y²=3[(x+2y/3)²-4y²/9]-y²=3(x+2y/3)²-4y²/3-y²=[(√3)(x+2y/3)]²-[y√(7/3)]²=[(√3)(x+2y/3)+y√(7/3)][(√3)(x+2y/3)-y√(7/3)]=(1/3)[(3x+2y...
3x2+4xy-y2=3（x2+43xy-13y2）=3[（x2+2×23xy+49y2）-13y2-49y2]=3[（x+23y）2-79y2]=3（x+23y+73y）（x+23y-73y）=3[x+2+73y）（x-2?73y）．
3x²+4xy-y²因式分解 有过程 解：3x²+4xy-y²=3(x²+4xy/3)-y²=3[(x+2y/3)²-4y²/9]-y²=3(x+2y/3)²-4y²/3-y²=[(√3)(x+2y/3)]²-[y√(7/3)]²=[(√3)(x+2y/3)+y√(7/3...