Simplify this expression: 2/y^2 - 3y + 2 + 7/y^2 -1 Simplify the expression. (7 + 5) + 4 \times 13 - 2 Simplify the expression (x^2 + x - 6) / (x^2 + 2x - 3) + (x - 4) / (x^2 - 3x + 2) Simplify the following expression: \dfrac{1}{sin^2x-cos^2x}-\df...
To solve the problem, we need to follow these steps:Step 1: Identify the expressions We have two expressions: 1. \( x^4 + x^3y^2 + x^2y^3 + y^4 \) (the expression from which we will subtract) 2. The sum of \( -3x^3y^2 + 2x^2y^3
Answer: The given system has infinitely many solutions. Practice Questions on Cramer's Rule Q. 1 The solution of the system of equations 2x - y = 1 and x - 3y = 8 using Cramer's rule is, x = ; y = Check Answer Q. 2 Tick every option that applies. For finding the solution of...
- (4/3)C = -8 Solve: 2x - \sqrt{ 3x^2 - 4x -4}. Solve: (x - 5)/(x - 4) + 8/(x^2 - 16) = 0. Solve \frac{dy}{dx} = 4xy^2 Solve: [cot(3x)](dy/dx) - 3y = cos(3x) + sin(3x). Solve: (5y-9)(7y-10)=0 Solve: (5x - 3)^2 = -3. Solve: x + ...
Answer to: Find the area of the region bounded by y=2x and y=x^2+3x-6. Evaluate and sketch. By signing up, you'll get thousands of step-by-step...
See Answer Question: Question 4 Find the Wronskion of 1-2x + 3y = x + 3a. and y = x - 1. Use the result to determine if the three functions are linearly independent on (-0, o). W (22+3, 2+ 32, 22-1) - Are the fu...
4. Calculate the denominator: - Calculate A2+B2: A2+B2=22+12=4+1=5 - Therefore, the denominator becomes: √A2+B2=√5 5. Combine the results: - Now substitute back into the distance formula: d=7√5 6. Final answer: - The distance between the two parallel lines is: d=7√5Updated...
Answer and Explanation:1 Given: The given expression is {eq}y''' - 2y'' + 2y' + 3y{/eq}. The value of {eq}y{/eq} is {eq}y = {e^{2x}}{/eq}. Let us find the first... Learn more about this topic: Finding Derivatives of a Function | Overview & Calculations ...
(x-3)→ye-3y-2x+5→y2x-2x-3y+5x(y2)=3y|5⇒x=(3y-5)/(y-2)(0.9y=(3x+5)/(x-2))g^(-1)(x)-(3x+5)/(x-2),2x≤(15)/2Way 2: y-(2x+6-11)/(x-3)→y-2+(11)/(x-3)→y-2-(11)/(x-3)x-3=(11)/(y-2)⇒x=(11)/(y-2)+3(0+y)=(11)/(x-2)+...
应先消去未知数(x)得到关于(y,z)的二元一次方程组,得(y+z=5,3y+2z=12),原方程组的解是(1,2,3).故答案为:x=1, y=2, z=3. li:after{clear:both}.Afanti_options>li+li{margin-top:5px}.label-answer{float:left;padding:0 5px;font-family:Helvetica,Arial,sans-serif;font-style...