首先，除以5余4，说明这个数个位是4或9；接着，除以23余7，能整除23且小于100的数，只有四个，分别是23,46,69,92,；然后个位数加上7，所得的个位数恰好是4或9；最后答案是99。
Your answer is the top number, and any remainder will be the bottom number. So, for 23 divided by 242, the final solution is: 0 Remainder 23 Cite, Link, or Reference This Page If you found this content useful in your research, please do us a great favor and use the tool below to ...
Lesson 11: Divides 3- to 4-Digit Numbers by 1-to 2-Digit Numbers Without and With Remainder. YouTube 更多視頻 來自Web 搜索的類似問題 How do you evaluate 12−8÷2 ? https://socratic.org/questions/how-do-you-evaluate-12-8div2 8 Explanation: Count the number of terms first. There ar...
However, nearly the same number are maternally or paternally assigned through Family Matching, with the remainder unassigned. You can read about Family Matching here. Match Category FamilyTreeDNA Test Ancestry V1 at FamilyTreeDNA Ancestry V2 at FamilyTreeDNA Paternal 3,479 3,572 3,422 Maternal 1,...
1 shows a block diagram of the system for receiving mandated input parameters, a processor for implementing the mandated parameters through selection and implementation of variable parameters, and interfaces to the user and the remainder of the system. [0062] FIG. 2 is a block diagram flow chart...
百度试题 结果1 题目When a number is divided by 23, the quotient is 12 and the remainder is larger than 0. The largest possible value of this number is . 相关知识点: 试题来源: 解析 287
remainder of the collar remains in sealed sliding engagement with the cylinder block to seal the port 22 from the intake chamber for a portion of the rotational path of port 22. The exhaust collar 21a is shown in FIG. 24. It includes an opening 55 extending along its length to be ...
GCF of 92 and 23 is the largest possible number which divides 92 and 23 without leaving any remainder. The methods to compute the GCF of 92, 23 are explained here.
multiply ,multiplied by 乘,乘以 multiple, factor 倍数,商 times 倍数 product 乘积 once, twice, three times … ten times 一次,两次,三次,...十次 repeated addition 叠加 division 除法 dividing, divide, divided by, divided into 除,除以 ...
Polypeptides that include the core structure (e.g., WX1W, WX1X2X3W, WX1X2X3X4X5X6W, and the like) have the ability to bind IL-23R and inhibit IL-23 notwithstanding the remainder of the polypeptide sequence. The second class of the screened polypeptides encompasses novel polypeptides that...