(2+4+6+……+100)-(1+3+5+……+99) =(2-1)+(4-3)+(6-5)+……+(100-99) =1+1+1+……+1 =1×50 =50 答:所有奇数的和与所在偶数的和之间相差50。 1.本题是数与代数类型的题目; 2.把1～100的所有偶数的和减去所有奇数的和; 3.列出算式再简便计算出结果。结果...
while (i<=100){if(i%2==0){scount2 +=1;ssum2 +=i;}else{scount1 +=1;ssum1 += i;}i++;}document.write ("奇数的个数是:"+scount1+"");document.write("所有奇数之和为:"+ssum1+"");document.write ("偶数的个数是:"+scount2+"");document.write("所有偶数之和为:"+ssum2+"...
百度试题 结果1 题目【简答题】计算 1 ~ 100 之间所有奇数之和以及所有偶数之和 相关知识点: 试题来源: 解析 计算1 ~ 100 之间所有奇数之和以及所有偶数之和。 答案: #include void main() { int i,a=0,b=0; for(i=1;i 反馈 收藏
include "stdafx.h"int _tmain(int argc, _TCHAR* argv[]){int s1=0;//偶数的和int s2=0;//奇数的和int g1=0;//偶数个数int g2=0;//奇数个数for(int i=1;i<=100;i++){if(i%2==0){s1=s1+i;g1=g1+1;}else{s2=s2+i;g2=g2+1;}};printf("偶数的个数为：%d\n...
1.s2=0 2.t=i+1
计算1 - 100之间所有奇数的和,偶数的和,3的倍数的和 varnum = 1;varnum1 = 1;varoddSum = 0;varevenSum = 0;vartimesSum = 0;while(num <= 100){if(num % 2 == 0) { evenSum= evenSum +num; }elseif(num % 2 == 1) { oddSum= oddSum +num;...
declare @i int,@Jsum int,@Osum int set @i=1 set @Jsum=0 set @Osum=0 while(@i<=100)begin if(@i%2=0)set @Osum=@osum+@i else set @Jsum=@Jsum+@i set @i=@i+1 end select @Jsum as '奇数和',@Osum as '偶数和'得出结果 奇数和：2500 偶数和:2550 ...
计算1-100之间所有奇数的和，偶数的和，3的倍数的和var num = 1;var num1 = 1;var oddSum = 0;var evenSum = 0;var timesSum = 0;while(num <= 100){ if (num % 2 == 0) { evenSum = evenSum + num;}else if (num % 2 == 1) { oddSum = oddSum + num;} num++;} while (...
奇数=5000 偶数=5100 差100
var i=1;var sum1=0;var cont1=0;var sum2=0;var cont2=0;while(i<100){ if(i%2==0){ sum1+=i count1++;}else{ sum2+=i count2++;} i++;} alert("奇数之和"+sum1+"奇数总数"+count1);alert("偶数之和"+sum2+"偶数总数"+count2);...