lim趋向于0(1+tanx)/(1+sinx)∧1/x3 答案 lim [(1+tanx)/(1+sinx)]^(1/x^3)=lim [1+(tanx-sinx)/(1+sinx)]^[(1+sinx)/(tanx-sinx)*(tanx-sinx)/(1+sinx)*1/x^3]=e^lim (tanx-sinx)/x^3 * 1/(1+sinx)=e^lim tanx(1-cosx)/x^3*1/(1+0)=e^lim (x*x^2/2)/x^...
求极限,难难难,急 如何求极限:(x→0)lim[(1+tanx)/(1+sinx)]^(1/x^3) 1.先取对数. 2.利用洛必达法则,可以得到lim co
=e^[lim(x->0)tanx(1-cosx)/x³]=e^[lim(x->0)(x·x²/2)/x³]=e^(1/2)
答案是根号(e)，注意公式的运用。
=explimx→02(tanx−sinx)x3=e.
答案是根号(e),注意公式的运用.lim-|||-1+tanx-|||-X→0-|||-1+sinx-|||-tanx-sinx-|||-=lim-|||-1+-|||-X→0-|||-1+sinx-|||-1+sinx tanx-sinx 1-|||-=lim-|||-tanx-sinx-|||-tanx-sinx 1+sinx-|||-x3-|||-1+-|||-X→0-|||-1+sinx-|||-lim-|||-tanx-sinx...
lim_(x→0)((1+tanx)/(1+sinx)^(1/(x^3))=lim_(x→0)[1+((1+tanx)/(1+sinx)-1)]^(1/(x 解limx→0∵lim_(x→0)(tanx-sinx)/(1+sinx)+1/(x^3)=l+sinx)cosx_(x→0)⋅1/(x^3) =lim_(x→0)(sinx)/x⋅(1-cosx)/(x^2)⋅1/((1+sinx)cosx)=1/2∴原式=e...
lim [(1+tanx)/(1+sinx)]^(1/x^3)=lim [1+(tanx-sinx)/(1+sinx)]^[(1+sinx)/(tanx-sinx)*(tanx-sinx)/(1+sinx)*1/x^3]=e^lim (tanx-sinx)/x^3 * 1/(1+sinx)=e^lim tanx(1-cosx)/x^3*1/(1+0)=e^lim (x*x^2/2)/x^3 =e^(1/2)=√e ...
limx→0xsinx−1tanx⋅lnx=limx→0esinx⋅lnx−1tanx⋅lnx...
以上，请采纳。