发现三角函数是现在为数不多的大中衔接的漏洞了,所以写一点东西 余切定义: \cot\theta = \frac{1}{\tan\theta} \:or\:\cot\theta = \frac{\cos\theta}{\sin\theta} 函数图像: 不难发现: \cot\theta = \tan(\fr…
Show that (1)/( cos theta ) -cos theta =tan theta .sin theta 01:57 Simplify sec A (1-sin A ) (secA+tan A) 02:19 Prove that (sin A +cosec A) ^(2) +(cos A +sec A) ^(2) =7+ tan ^(2) A +... 03:20 Simplify (1-cos theta ) (1+cos theta ) (1+ cot ^(2)...
\tan\theta=\frac{\sin\theta}{\cos\theta}.正弦值（sin1°）的精确值是约为0.01745240643728351。
यदि tan theta =3/4 तो (1-cos theta )/(1+cos theta) का मान ज्ञात करो । 03:30 यदि tan theta =(12)/(5) तो (1+sin theta)/(1-sin theta) का मान ज्ञात क... 05:24 यदि cot...
∴sin\theta =2cos\theta tan^2\theta =\frac{1-cos^2\theta }{cos^2\theta }=\frac{1}{cos^2\theta }-1=4 ∴cos^2\theta =\frac{1}{tan^2\theta +1}=\frac{1}{5} ∴1+sin\theta cos\theta =1+2cos^2\theta =1+\frac{2}{5}=\frac{7}{5} 故选B.反馈...
7.证明下列恒等式:(1)$$ \tan \theta \cdot \fra c { 1 - \sin \theta } { 1 + \cos \theta } = \cot \theta \cdot \fra c { 1 - \cos \theta } { 1 + \sin \theta } ; $$(2)$$ \fra c { 1 + \tan ^ { 4 } \alpha } { \tan ^ { 2 } \alpha + \co...
If : tantheta+cottheta=2,"then": sintheta+costheta 01:12 सिद्ध कीजिए कि : (tantheta)/(sectheta-1)+(sintheta)/(1+costheta)=2c... 03:23 (1/costheta-costheta)(1/(sintheta)-sintheta)=(1)/(tantheta+cottheta). 03:30 ("sin"theta)/(1-costhe...
asinx+bcosx=a2+b2⋅sin(x+φ) 其中sinφ=ba2+b2,cosφ=aa2+b2 二倍角公式 sin2x=2sinxcosx=2tanx1+tan2xcos2x=cos2x−sin2x=1−2sin2x=2cos2x−1=1−tan2x1+tan2xtan2x=2tanx1−tan2x 三倍角...
tan theta = -1, cos theta = (1)/(sqrt(2)) का व्यापक हल है -
【题目】证明下列恒等式:(1)$$ \tan \theta \cdot \fra c { 1 - \sin \theta } { 1 + \cos \thet