自定义函数题:写一函数计算n!,并调用它计算 1! + 2! + ... + k!相关知识点: 试题来源: 解析 #include "stdio.h" int factor(int n) { int i,t=1; for (i=1;i<=n;i++) t=t*i; return t; } void main() { int k,i,s=0; scanf("%d",&k); for (i=1;i<=k;i++) ...
写一个函数,输入一个整数n,输出从1到n的所有数字的平方。相关知识点: 试题来源: 解析 答案示例: ```python def square(n): result = [] for i in range(1, n+1): result.append(i ** 2) return result n = int(input("请输入一个整数:")) print(square(n)) ```...
#include int main(void) { int n; int sum(int n), scanf("d",&n); printf("sum=%d n",sum(n)); return 0;} int sum(int n) } int result,i; result =0; for(i=1;i<=n;i++) result result i; return result;}若要计算m~n(m反馈...
解析 float fac(int n){ float f; if(n<0){printf("n<0,dataerror!";} else if(n==0||n==1)f=1; else f=fac(n-1)*n; return(f);}main(){ int n; float y; printf("input an integer number:"); scanf("%d",&n); y=fac(n); printf("%d!=%10.0f",n,y);...
char * myfunc(int n){ char *a=(char *)malloc(sizeof(char)*(n+1));int i=0;for (i=0;i<n;i++)a[i]='a';a[n]='\0';return a;} main(){ int n;scanf("%d",&n);char *a;a=myfunc(n);printf("%s\n",a);} ...
int main (){ int i,n;printf("请输入n值：");scanf("%d",&n);printf("1!+2!+...+n!=%d\n",Sum(n));return 0;} int Func(int n) //递归求n!{ int sum=1;if(n==1 || n==0)return 1;else sum=n*Func(n-1);return sum;} int Sum(int n) //求1！+2！+...
include "stdio.h"main(){ int fun(int n);int n;scanf("%d",&n);if(n>=1)printf("1+2+...+%d=%d\n",n,fun(n));else printf("error\n");} int fun(int n){ int s=0;while(n>=1){s +=n;n--;} return s;} ...
(在vc++6.0和turbo c 2.0中一样)include<stdio.h> int sum(int n){ int s=0;for(int i=1;i<=n;i++){ s=s+i;} printf("%d\n",s);} void main() /*在turbo c 2.0 中不加void*/ { int n;printf("请输入要求和的自然数的个数n:\n");scanf("%d\n",&n);sum...
写一函数,用来求表达式1+2+3+...+n的值,并编写主函数。n由键盘输入。 Input 输入一个整数 Output 输出表达式的值 Sample Input 5 Sample Output 15 #include <stdio.h> int sum(int n) { int a; if(n==0) a=0; else a=sum(n-1)+n; return...
任意输入一个数n,写一个1+2+3+的函数,在主函数中输入n,且输出1+2+3+n的值, 要求使用函数调用 #include "stdio.h" main() { int fun(int n); int n; scanf("%d",&n); if(n>=1) printf("1+2+...+%d=%d\n",n,fun(n)); else printf("error\n"); } int fun(int n) { int s...