};intmain(){ AVLtree t; cout<< t.initiation()->data;return0; }
04-树5 Root of AVL Tree 这道题目要求找出AVL树的根节点,重点考查了AVL树的旋转(右单旋、左单旋、右-左双旋和左-右双旋)与插入操作。 1#include <stdio.h>2#include <stdlib.h>34typedefstructAVLNode *AVLTree;5typedefintElementType;6structAVLNode {7ElementType Data;8AVLTree Left, Right;9intHeig...
int GetLevel(Tree T); //获得本树层数 Tree LLrotation(Tree T); // LL旋转 Tree LRrotation(Tree T); // LR旋转 Tree RRrotation(Tree T); // RR旋转 Tree RLrotation(Tree T); // RL旋转 //主函数 int main() { int N; scanf("%d", &N); Tree T = BuildTree(N); printf("%d", ...
Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree. Input Specification: Each input file contains one test case. For each case, the first line contains a positive integer N (≤20) which is the total number of keys to be inserted. Then N di...
04-树5 Root of AVL Tree (25分) An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4...
数据结构1 - 04-树5 Root of AVL Tree 1 #include<stdio.h> 2 #include<math.h> 3 #define MAXN 1000 4 struct node{ 5 int left,right,data,height,parent; 6 }; 7 struct node a[MAXN]; 8 int n; 9 void read(); 10 void updateHeight(int x); 11 int getfactor(int x); 12 int ...
Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree. Input Specification: Each input file contains one test case. For each case, the first line contains a positive integerN (≤20) which is the total number of keys to be inserted. ThenN distin...
Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree. Input Specification: Each input file contains one test case. For each case, the first line contains a positive integerN (≤) which is the total number of keys to be inserted. ThenNdistinct ...
04-树5 Root of AVL Tree An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4 ...
Root)return;elseif(father[ARoot] > father[BRoot])//B树深度大于A树{/*树的深度不变*/father[ARoot]= BRoot;//将A树指向B树}else{if(father[ARoot] == father[BRoot])//两树深度相等father[ARoot]--;//树的深度加1,根节点对应数组的值(非正数)的绝对值为这棵树的深度father[BRoot] =ARoot...