= len(s): substrings.append(s[startIndex:]) # 输出存放所有子串的字符串数组 return substrings # 测试字符串 input_string = "abc acedw iikj*hikk*jhybn uybhj klij*kklwq nnnm*kijuh*kileq dddfg" # 调用函数并打印结果 result = find_continuous_substrings(input_string) print(result) 输出...