app跳转小程序 微信开放平台已关联小程序 然后代码中这样写的 WXLaunchMiniProgramReq *launchMiniProgramReq = [WXLaunchMiniProgramReq object]; launchMiniProgramReq.userName = @""; //拉起的小程序的username launchMiniProgramReq.path = nil; //拉起小程序页面的可带参路径,不填默认拉起小程序首页 launchMiniP...
您好，解决了吗？
微信开发平台已关联小程序,跳转username也是以gh_开头。 对应跳转代码如下 WXLaunchMiniProgramReq *launchMiniProgramReq = [WXLaunchMiniProgramReq object]; launchMiniProgramReq.userName = @"gh_"; //拉起的小程序的username launchMiniProgramReq.path = @"pages/home/home"; //...
上图是微信文档的示例，但我们进入到详情看不到关联小程序的按钮
let launchMiniProgramReq = WXLaunchMiniProgramReq.object() launchMiniProgramReq.userName ="gh_31a6**...
https://developers.weixin.qq.com/doc/oplatform/Mobile_App/Launching_a_Mini_Program/iOS_Development...
https://developers.weixin.qq.com/doc/oplatform/Mobile_App/Launching_a_Mini_Program/iOS_Development...
咋解决的啊
安卓App内部跳转小程序,移动应用的appid(wx开头)和小程序的原始id(gh_开头)都没错,但是跳转微信报bad_param提示弹窗,关闭弹窗停留在微信界面,没有正确的跳转到微信小程序,请技术人员帮忙看看什么原因造成的???谢谢
APP跳小程序？