结果1 题目 编写程序,要求打印出如下的内容 1 2 3 4 5 2 3 4 5 3 4 5 相关知识点: 试题来源: 解析 (参考) Private Sub Form_Load() For i = 1 To 5 For j = i To 5 Print j; Next j Print ”” Next i End Sub 反馈 收藏 ...
1、双击Python安装包,如下图:2、注意:要选中Add Python 3.x to PATH==, 点击“Cust 用python编程 s='I like python very very much用python语言编写程序。找出三位数中能被17整除的数逐行输出,并统计个数,最后输出总个数? python程序如下: count = 0 # 用来统计能被17整除的三位数个数 for i in range...
计算1*2*3 + 3*4*5 + ... + 99*100*101 程序代码：sum = 0 i = 1 while i < 100:sum += i * (i + 1) * (i + 2)i += 2 print(sum)运行结果：13002450
for i in range(1,100):s = s + i*(i+1)*(i+2)print(s)S = 25497450
#includevoid main{ int s=0； for(int i=1；i<100；i+=3) s+=i*(i+1)*（i+2); cout<...
'1、* 编写程序,计算并输出下面数列中前n项的和.(设n=20)' 1*2*3,2*3*4,3*4*5,……,n(n+1)(n+2),…… Dim sum&, i%, temp%, n% n = Val(InputBox("n=", , 20)) For i = 1 To n temp = i * (i + 1) * (i + 2)...
total=sum([i*(i+1)*(i+2) for i in range(1,100,2)])print(total)
main(){ long sum = 1;int i;int sum0 = 0;clrscr();for(i=1; i<=100; i++){ sum *= i;if(sum % 10 ==0){ sum0++;sum = sum / 10; /*此处可不使sum的值过大而超出long类型的范围*/ } } printf("%d",sum0);} 注，最后的sum0即是1到100相乘数后的0数（65个...
public class Test{ public static void main（String[] args){ //输出12345 for(int a=1;a<=5;a++){ system.out.print(a);} //输出1到10之内的奇数 for(int a=1;a<=10;a++){ if(a/2!=0){ system.out.print(a);} } } } 我尽力了，望采纳 ...
res = 0 for i in range(1, 100):cur = i for j in range(1, 2):cur *= (i + j)res += cur print(res)