while (i<=100){if(i%2==0){scount2 +=1;ssum2 +=i;}else{scount1 +=1;ssum1 += i;}i++;}document.write ("奇数的个数是:"+scount1+"");document.write("所有奇数之和为:"+ssum1+"");document.write ("偶数的个数是:"+scount2+"");document.write("所有偶数之和为:"+ssum2+"...
#利用while循环打印从0-10的数字 num = 0 while num<=10: print(num) num+=1 1. 2. 3. 4. #练习二 #利用while循环,计算1-100之间数字的累加和;计算1-100之间偶数的累加和,计算1-100之间奇数的累加和 num = 0 sum_all = 0 sum_even = 0 sum_odd = 0 while num<=100: sum_all += num ...
while(i<100){ if(i%2==0){ sum1+=i count1++;}else{ sum2+=i count2++;} i++;} alert("奇数之和"+sum1+"奇数总数"+count1);alert("偶数之和"+sum2+"偶数总数"+count2);
Untitled Document < int A = 0, B = 0, i = 0;while (i++ < 101) { if (i % 2 == 0) { A += i;} else { B += i;} out.println("(while)偶数的和为:" + A + ".");out.println("(while)奇数的和为:" + B + ".");} > < int a = 0, b = 0, j...
编程.循环语句.用Do While...Loop形式①编程计算s=1+2+3+……+100的值.②编程计算1到100之间所有偶数的和,要求Step值为2.③请用不同的循环语句实现:在程序运行过程中任意输入一个自然数n,求1到n
1.输入三个整数,将它们从大到小排序输出.2.编程利用do-while语句实现100以内的能被5整除的数累加.3.某人有100元,欲买100只鸡,公鸡5元一只,母鸡3元一只,小鸡一元3只,问可买到公鸡、母鸡、小鸡各多少只?4.有一个数列,前两个数是1和1,第三个数是前两个数之和,以后的每个数都是前两个数之和,要求输出...
while (i++ < 101) { if (i % 2 == 0) { A += i;} else { B += i;} out.println...