for a in range(1,100):k = 0 for i in range(2,a):if a % i == 0 :k += 1 if k == 0 :print a b +=1 print "素数一共有",b,"个"素数：一个数只能被1 和它本身整除，则该数即为素数
range(2,int(n**(1/2))+1):if n i == 0:break else:primes += [n]print(primes)print(f'100内有{len(primes)}个素数')程序 缩进 如图所示
以下是实现该逻辑的代码：```python# 定义一个函数，用于检查一个数是否为素数def is_prime(num): if num <= 1: return False for i in range(2, int(num ** 0.5) + 1): if num % i == 0: return False return True# 遍历1到100的偶数for even_number in ran...
“`python def is_prime(num): if num < 2: return False for i in range(2, int(num ** 0.5) + 1): if num % i == 0: return False return True def find_primes(start, end): primes = [] for num in range(start, end+1): if is_prime(num): primes.append(num) return primes p...