请使用一趟扫描完成反转。说明:1≤ m≤ n≤ 链表长度。示例:输入: 1->2->3->4->5->NULL, m = 2, n = 4输出: 1->4->3->2->5->NULL思路:思路较简单,找到规律就好。程序:# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next =...
反转从位置 m 到 n 的链表。请使用一趟扫描完成反转。 /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/classSolution {publicListNode reverseBetween(ListNode head,intm,intn) {if(head ==null|| head.n...