while实现程序源代码:#include "stdio.h"void main(){int i=1,sum=0;while(i<=100){sum=sum+i;i++;}printf("1+2+3+4+……+100=%d\n",sum);}do-while实现程序源代码:#include "stdio.h"void main(){int i=1,sum=0;do{sum=sum+i;i++;}while(i<=100)printf("1+2+3+4+……+100=...
题目编程实现:使用do...while语句求1到100的奇数和 要求从类开始写起 相关知识点: 试题来源: 解析 第一种: class CalculateSum1To100Odd { public string Sum1To100Odd() { int i=1,sum=0; do { sum+=i; i+=2; }while(i 反馈 收藏
int i = numberOne; int sum = 1; while (numberOne < numberTwo) { sum = sum + numberOne; numberOne++; } Console.WriteLine("从{0}到{1}之和为{2}", i, numberTwo, sum);int i=1; int sum = 0; do { sum = sum + i; i++; }while(i 反馈...
//1、使用do-while int sum = 0; //当前之和 int i = 1; //加数 do { if (i%2==0){ sum+=i;} i++;}while (i<=100);System.out.println(sum);--- //2、使用wihle的做法：int sum = 0; //当前之和 int i = 1; //加数 while (i<=100){ if (i%2==0){...
计算1到100的和值，do-while使⽤范例/*计算1、2到100的和值，while使⽤范例*/ #include<stdio.h> #include<stdlib.h> int main(void){ int i,sum=0;/*初始化*/ printf("\nWelcome.\n""Calculate the result of 1+2+...+100\n\n");i=1;do/*开始do-while循环*/ { sum+=i;/*计算和...
/** * @author hardneedl */public class h { public static void main(String... args) { int i = 1,sum = 0; do { sum += i++; }while(i<=100); System.out.printf("sum = %d", sum); }}
用java编写使用do-while循环语句实现计算1~100之和，如下：package com.test;public class TestA {public static void main(String[] args) {//计量int count=0;//总是int sum=0;//do循环不管while循环条件，都会执行一次do{sum+=count;count++;//只要count还满足while,那还会执行一次，直到不满足...
/*计算1、2到100的和值,while使用范例*/ #include<stdio.h> #include<stdlib.h> int main(void) { int i,sum=0;/*初始化*/ printf("\nWelcome.\n" "Calculate the result of 1+2+...+100\n\n"); i=1; do/*开始do-while循环*/ ...
1 package com.workprojects; 2 /** 3 * 使用while循环求出1-100的偶数之和 4 * 2019-06-28 5 * @author L 6 */ 7 8 public class Work062802 { 9 public static void main(String[] args) { 10 int num = 0; 11 int sum = 0; 12 while(num<=100) { 13 sum += num; 14 num +=...
I=1 DO WHILE I<101 SUM=SUM+I I=I+1 ENDDO ?’1~100的总和为:’,SUM 例2:累乘:求n! clear INPUT "求n!,请输入n的值:" TO N MUL=1 FOR I=1 TO n MUL=MUL*I ENDFOR ?n,’的值为:’,MUL 例3:输入n的值,求1+1/2!+1/3!+1/4!+….+1/n! ( 阶乘 n!=1*2*3*4...*(n...