6.使用递归完成1到100的累加 function sum(num) { if( num==1 ){ return 1; } return num+sum(num-1); } console.log(sum(100))
function sum(n) { if (n <= 1) return n return sum(n - 1) + n}// test sum(100)sum(10)sum(2)sum(1)
function sum(num) { if( num==1 ){ return 1; } return num+sum(num-1); } console.log(sum(100))