#include"iostream" using namespace std; // 宏定义 #define N 6 #define R 2 #define C 3 // 引用自定义函数 void inputOne(int *pData,int m,int n); void printOne(int *pData,int m ,int n); int main(){ int a[R][C]; inputOne(&a[0][0],R,C); printOne(&a[0][0],R,...
include <stdio.h> // 函数声明：找出二维数组中的最大数 int findMax(int arr[][3]);int main() { int numbers[4][3]; // 定义一个4行3列的二维数组 // 输入12个数 printf("请输入12个数：\n");for (int i = 0; i < 4; i++) { for (int j = 0; j < 3; j++) ...
void inputdata(int *a) { int i,j; for ( i=0;i<3;i++ ) for ( j=0;j<4;j++,a++ ) scanf("%d",a);}void outputdata(int *a) { int i,j; for ( i=0;i<3;i++,printf("\n") ) for ( j=0;j<4;j++,a++ ) printf("%d ",*a);} ...
include <stdio.h> int a[10][10];int main(){ int i , j;//input data for( i = 0; i < 10; i++)//多少行 { for(j = 0; j < 10; j++)//多少列 { scanf("%d", &a[i][j]);//输入第i行j列的值 } } //ouput data for( i = 0; i < 10; i++){ for(...
C程序设计:p216t10,偷懒写法,用strlen和二维数组---写一个函数,输入一行字符,将此字符串中最长的单词输出 15:38 C程序设计:P216T10,写一个函数,输入一行字符,将此字符串中最长的单词输出 18:19 C程序设计:函数的嵌套调用以及递归调用 17:51 C程序设计:课后题P216T7,写一个函数,将一个字符串中的元音...
include <stdio.h>int sum(int *a, int n){ int i,r=0; for(i = 0; i < n; i ++) if(a[i]%2) r+=a[i]; return r;}int main(){ int a[10]; int i,r=0; for(i = 0; i < n; i ++) scanf("%d",a+i); r = sum(a,10); ...
// wer.cpp : Defines the entry point for the console application.// include "stdafx.h"include <stdio.h> include <string> using namespace std;int main(int argc, char* argv[]){ int sum;int n;int score[5][3]=;printf("输入最低分数和：");scanf("%d",&n);for(int i=0...
int i, j ;for(i=0; i<3; i++)for(j=0; j<2; j++)printf("a[%d][%d] is: \n", i, j, a[i][j]);} void main(){ int i, j ;int a[3][2]={{1,0},{2,0},{3,0}};int (*p)[2]=&a[0];for(i=0; i<3; i++)for(j=0; j<2; j++)printf("a[...
private sub form_click()dim a(3,4) as integer,i as integer,j as integer dim max(3) as integer for i=1 to 3 for j=1 to 4 a(i,j)=val(inputbox(“a(”&i&“,”&j&“)=”,“输入”,i))next next max(1)=a(1,1)max(2)=1 max(3)=1 for i=1 to 3 for j...
include <stdio.h>#include <stdlib.h>void getscore(float s[6][5]){ int i,j; float t; for(i=0;i<5;i++) for(j=0;j<4;j++) { scanf("%f",&t); s[i][j]=t;}}void printscore(float s[6][5]){ int i,j; for(i=0;i<6;i++){ for(j=0;j<5;j++...