解析 You getx= (-b± √ (b^2-4ac))(2a)= (-(5)±√ ((5)^2-4(1)(-3)))(2(1))= (-5± √ (37))2=- 52± (√ (37))2The solution of the equation x^2+5x-3=0 is x such thatx=- 52± (√ (37))2.反馈 收藏 ...
( x^2+10x-3) 相关知识点: 试题来源: 解析 Use the quadratic formula to find the solutions.( (-b± √(b^2-4(ac)))/(2a))Substitute the values ( a=1), ( b=10), and ( c=-3) into the quadratic formula and solve for ( x).( (-10± √((10)^2-4⋅ (1⋅ -3)))/(...
The quadratic formula is stated as x=−b±b2−4ac2a. This formula is used to solve quadratic equations in the form of ax2+bx+c=0. The values of x calculated using the quadratic formula are as well known as the roots of the equation....
Explanation: We need to solve the distance formula for x2+5x=500 . This is a quadratic: x2+5x−500=0 We can factorise this ... How do you find the equation of the tangent line to the curve −x2+5x at (-1,-5)? https://socratic.org/questions/how-do-you-find-the-equation...
A quadratic equation represented as ax2+bx+c=0 may contain two complex roots if its discriminant value D=b2−4ac is negative, specifically b2−4ac<0. In order to find the complex roots, the quadratic formula for two solutions, x1 and x2 is used, so that x1,2=−b±D2a is ...
A. Solve each quadratic equation using the quadratic formula (14 points)1. x^2+6x+9=02. x^2+7x+10=03. x^2+4x-21=0 相关知识点: 试题来源: 解析 -3;-2;-5;-7;3 x^2+6x+9=0: 解:x=-3 x^2+7x+10=0: 解:x=-2, x=-5 x^2+4x-21=0: 解:x=-7, x=3反馈 收藏 ...
The polynomial 3x² − 5x + 4 is written in descending powers of x. The first term has coefficient 3, indeterminate x, and exponent 2. In the second term, the coefficient is −5. The third term is a constant. Because the degree of a non-zero polynomial is the largest degree of...
Answer to: Solve 2x = 5x^2 for x. By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also ask your...
aWhere shall we meet? 我们在哪里将见面?[translate] aHow could you apply either of the two versions of the quadratic formula which we have considered to solve the equation x2= 5x + 14? 您怎么可能运用我们考虑解决等式x2= 5x + 14二次方惯例的二个版本之一?[translate]...
x2+17x+72=0x2+17x+72=0 Utilizza la formula quadratica per trovare le soluzioni. −b±√b2−4(ac)2a-b±b2-4(ac)2aSostituisci i valori a=1a=1, b=17b=17 e c=72c=72 nella formula quadratica e risolvi per xx. −17±√172−4⋅(1⋅72)2⋅1-17±172-4⋅(1...