题目【题文】已知x=2y=3是方程5x-ky=7的一个解,则k = . 相关知识点: 二元一次方程(组) 二元一次方程(组)的概念 二元一次方程 二元一次方程的解 试题来源: 解析 【答案】1【解析】把x=2 y=3代入方程可得5×2-3k=7,k=1. 反馈 收藏
L_(2)=3x-ky-1=0, L_(3)=5x+2y-12=0 are concurrent if k= For what value of k does the system of equations x+2y=3 and 5x+ky+7=0 have no solution Find the value ofkfor which the following system of equations has a unique solution:x+2y=3,5x+ky+7=0 View Solution Find k ...
x + 2y-5 = 0 మరియు 5x-ky + 7=0 సమీకరణాల జతకు సాధనలు లేకపోతే k విలువ...
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3x+2y=3k 2x+3y=7k x-y=-4k x=y-4k 3(y-4k)+2y=3k 5y=15k y=3k x=-k 解互为相反数 k=0 K
2.方程y=1-x与3x+2y=5的公共解是() A. 3.若5x-6y=0,且xy≠0,则的值等于() A.B.C.1D.-1 二、填空: 4.已知方程2x+3y-4=0,用含x的代数式表示y为:y=___;用含y的代数式表示x为:x=___. 5、若方程x-2y+3z=0,且当x=1时,y=2,则z=___; 6、方程2x+3y=10中...
1.1.3 certificate request entity 1.1.4 certificate request from 1.1.5 certificate request mode 1.1.6 certificate request polling 1.1.7 certificate request url 1.1.8 common-name 1.1.9 country 1.1.10 crl check 1.1.11 crl url 1.1.12 display pki certificate access-control-policy 1.1.13 display pk...
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5 k≠±1,k=0也满足.即可得出. 解答: 解:直线l1:x-y=0的斜率为1;l2:x+y-2=0的斜率为-1;l3:5x-ky-15=0.由于三条直线围成一个三角形,∴k≠0满足k= 5 k≠±1,k=0也满足.因此k∈R且k≠±5.故选:D. 点评:本题考查了两条直线平行于斜率的关系,属于基础题.练习册系列答案 实验...