解析 似乎就是说一个类如果它要被dll导出,它的所有基类都必须是基于dll的,而你的情况 结果一 题目 warning C4275:non dll-interface class 答案 似乎就是说一个类如果它要被dll导出,它的所有基类都必须是基于dll的,而你的情况是派生类是导出类,而基类不是 相关推荐 1 warning C4275:non dll-interface ...
Fix non-dll interface warnings from exception classes (#84) #375 Merged dalboris added a commit that referenced this issue Mar 6, 2020 Fix non-dll interface warnings from exception classes (#84) (#375) Verified fd72672 dalboris added a commit to dalboris/vgc that referenced this issue...
似乎就是说一个类如果它要被dll导出，它的所有基类都必须是基于dll的，而你的情况是派生类是导出类，而基类不是
I have problem understanding the real nature of warning C4275: non dll-interface class... In my case the exact error is this; 1>d:\projects\curlpp\include\curlpp\exception.hpp(49) : warning C4275: non dll-interface class 'std::runtime_error' used as base for dll-interface class 'curl...
I have problem understanding the real nature of warning C4275: non dll-interface class... In my case the exact error is this; 1>d:\projects\curlpp\include\curlpp\exception.hpp(49) : warning C4275: non dll-interface class 'std::runtime_error' used as base for dll-interface class 'curl...