随机变量或其分布的均值与方差的运算公式正确的有( )。 A. Var(aX+b)=a2Var(X)+b B. Var(X1+X2)=Var(X1)+Var(X2) C.
百度试题 结果1 题目随机变量或其分布的均值与方差的运算公式正确的有()。AVar(aX+b)=a2Var(X)+bBVar(X1+X2)=Var(X1)+Var(X2)CVar(X1-X2)=Var(X1)-Var(X2)Dσ(X1+X2)=σ(X1)+σ(X2) 相关知识点: 试题来源: 解析 B 反馈 收藏 ...
向量自回归(VAR,Vector Autoregression)模型是一种广泛用于时间序列分析的统计工具,特别是在经济学和金融学领域中。VAR模型的关键优势在于其可以捕捉多个变量之间的相互依赖关系,而无需预设变量之间的因果顺序。这使得VAR模型在处理复杂动态系统时极具灵活性。VAR模型
【答案】：E(Y)=E(3X+2)=3E(X)+2=26var(Y)=var(3X+2)=9var(X)=36$E(Y)=E(0.6X-4)=0.6E(X)-4=0.8var(Y)=var(0.6X-4)=0.36var(X)=1.44$E(X/4)=1/4E(X)=2var(X/4)=1/16var(X)=1/4$E(Y)=E(aX+b)=aE(X)+b=8a+bvar(Y)=a2var(X)=4a2 ...
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随机变量或其分布的均值与方差的运算公式正确的有( )。A Var(aX+b)=a2Var(X)+b B Var(X1+X2)=Var(X1)+Var(X2) C Var(
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Show that if Y = aX + b for some fixed constants a, b , then p(X,Y) = 1 if a greater than 0 and p(X,Y) = -1 if a less than 0 . For Q = (X + Y)(X^2+ Y^2) , find Q when X = 8 and Y = -2. Given the following data set for X and Y:...
Var(aX+bY)=a2var(X)+b2var(Y) Establish Eq. (B.17). Hint: Var (aX+ bY) = E[(aX + bY) - E(aX + bY)]2 and simplify.Explore our homework questions and answers library Search Browse Browse by subject Ask a Homework Question Tutors available × Our ...