用 using namespace std; 测试，没报错，状态显示 Accepted。我测试的时候是把 using std::istream;using std::cin;using std::cout;using std::endl;全部删除，然后只使用 using namespace std;。
using std::istream; using std::string;using std::vector; using std::map;mapxref(istream& in,vector find_words(const string&) = split){string line;int line_number = 0;map ret;while (getline(in,line)) {++line_number;vector words = find_words(line);...
using std::cout; using std::istream; using std::map; using std::ostream; using std::set; using std::string; using std::vector; // --- static void print_type_name(ostream& out, int t, CrushWrapper &crush) @@ -1248,8 +1255,8 @@ int CrushCompiler::compile(istream& in, const...
std::istream& operator>>(std::istream& in, SalesItem& s) { // ... } } //外部定义方式 cpp_primer::SalesItem cpp_primer::operator+(constSalesItem& lhs,constSalesItem& rhs) { SalesItem ret(lhs); // ... } 注意到外部定义方式,返回类型和函数名由命名空间名字限定。一旦看到完全限定的...
class istream: virtual public ios, public unsafe_istream {...}; The classstream_MTprovides the mutual exclusion (mutex) locks required to make eachiostreamclass MT-safe; it also provides a facility that dynamically enables and disables the locks so that the MT-safe property can be dynamically...
Error message: `getline(std::istream&, unsigned int&)' has no matching function . How can I solve this? Also, it outputs: 0 0 0 0 The output should be the correct value corresponding to the given input. #includeusing namespace std; ...
bool pelibIsBufferZeroed(const void * buffer, size_t length); std::uint64_t fileSize(const std::string& filename); std::uint64_t fileSize(std::istream& stream); std::uint64_t fileSize(std::ofstream& file);17 changes: 0 additions & 17 deletions 17 src/pelib/PeLibAux.cpp Original...
#include <iostream>#include<fstream> 添加成员函数定义: 1std::stringMyGlWindow::ReadShaderCode(constchar*fileName)2{3std::ifstream myInput(fileName);4if(!myInput.good())5{6std::cout <<"File failed to load..."<<fileName;7exit(1);8}9returnstd::string(10std::istreambuf_iterator<char...
std::istream &readLinesAndDoStuff(std::istream &input) { std::string line;while(std::getline(input, line)) { doStuff(line); }returninput;//traditional, not required if you want a different return type} If you want to read all the strings, you just need to push them into a vector ...
一、typename关键字 typename的第一个作用是用作模板里面,来声明某种类型,比如这样的: templatetypename _Tp, typename _Alloc> struct...typename在stl中还有另外一种作用,假设有这样一段代码: //test.cpp #include using namespace std; template...还有一种形式是: using std::cout; using std::endl...