Janis及Ficld (1959)报告23项条目版本的劈半信度系数为0.83,Spearman-Brown系数为0.91. Fleming及Watts (1980)版本和Fleming及Courtney(1984)版本的Cronbachα系数分别是0.90和0.92,尚无重测信度的资料。 FIS的聚合效度研究:Janis及Field版本与加州人格调查表中自尊测查部分的相关系数为0.67. Fleming JA Watt的版本与...
Janis及Ficld (1959)报告23项条目版本的劈半信度系数为0.83,Spearman-Brown系数为0.91. Fleming及Watts (1980)版本和Fleming及Courtney(1984)版本的Cronbachα系数分别是0.90和0.92,尚无重测信度的资料。 FIS的聚合效度研究:Janis及Field版本与加州人格调查表中自尊测查部分的相关系数为0.67. Fleming JA Watt的版本与...
The restrictive assumption of classical parallelism for the Spearman-Brown formulas makes them obsolete when the two-part alpha and coefficient alpha formulas can be used. The alpha coefficients require the less restrictive assumption of essential tau-equivalence. Even small reliability differences produced...
A Test of the Equality of Two Related α Coefficients Adjusted by the Spearman-Brown Formula S. (2000). A test of the equality of two related α coefficients adjusted by the Spearman- Brown formula. Applied Psychological Measurement, 24, 163-......
Spearman-Brown formula [¦spir·mən ′brau̇n ‚fȯr·myə·lə] (statistics) A formula to estimate the reliability of a testntimes as long as one for which reliability is known; the tests must be comparable in all aspects other than size. ...
用斯皮尔曼 (spearman) 等级相关计算各个策略之间的相关系数 ;4. 用皮尔逊 (Pear on) 积差相关统计词汇学习策略与总词汇量之间的相关系数 O 表 4 的统计结果表明 9 总体而言 Z 4 级和 Z 5 级学生 9 在学习策略方面都不突出 9 均值基本处于中值水平 (Z 分 ) 以下 O 几乎所有的管理策略的平均值均低于...
(RIBS),additinalitemattitudetowardpatientswithmentalillnessinlivelifeandtheunderstandingdegreeoftheMICA.Results:Theinternalconsistency(Cronbach’α)ofMICAChinesevisionwas0.720andtheSpearman-Brownsplit-halfcorrelationwas0.685.Thetest-retestreliabilitywas0.764(P﹤0.05).Thescalehadgoodfacevalidity.Itsnagetivecorrelation...
aSpearman rank correlations between abundance and sediment properties were calculated for the principal meiofaunal taxa (those with[100 individuals in all). 丰盈和沉积物产之间的用矛者茂盛的交互作用为主要meiofaunal罗汗松被计算了 (那些与(总计的100个个体)。[translate] ...
aThe Spearman rank-order correlation coeffi-cient between the scores of the two raters was.72, which is sufficiently high to be satisfying. 用矛者排列秩序相关系数在二名估价人之间was.72的比分,是充足地高满意。[translate] aI know, I'm not your girl friend, or what other people,But I still...
We could compute Pearson r, Spearman rho, or Kendall tau for each pair of judges and then average those coefficients, but we still would have the problem of high coefficients when the judges agree on ordering but not on magnitude. We can, however, compute the intraclass 若我们有超过二位法官...