Ifx2+bx+ca=0,x2+cx+ab=0have a common root then their other are the roots of the equation View Solution The quadratic equations : x2−6x+a=0andx2−cx+6=0 have one root in common. The other roots of the first and second equations are integers in the ratio 4 : 3. ...
<p>To solve the problem, we need to find the common root of the two quadratic equations given that they share one root and the other roots are in the ratio of 4:3. Let's go through the solution step by step.</p><p><strong>Step 1: Define the common root a
Consider a general quadratic with the coefficient of x1 being 1 and the roots being r and s. It can be factored as (x−r)(x−s) which is just x2−(r+s)x+rs. Thus, the sum of the roots is the negative of the coefficient of x and the product is the constant term. (In...
所以a=-3 a+1=-2 两个解是-2 -3 分析总结。 一题简单的英文版高级数学题结果一 题目 一题简单的英文版高级数学题.The quadratic equation x^2-x=k(x+1) has non-zero roots which differ by 1.Find the value of (i) each root,(ii)the constant k.翻译:二次方程 x^2-x=k(x+1)具有差...
A. ax+b=0 B. ax²+bx+c=0 C. ax³+bx²+cx+d=0 D. ax⁴+bx³+cx²+dx+e=0 相关知识点: 试题来源: 解析 B。“quadratic equation”是二次方程,其形式为 ax²+bx+c=0。选项 A 是一元一次方程。选项 C 是三次方程。选项 D 是四次方程。反馈...
Also, x2+mx+n=0 has roots 2a and 2b, so x2+mx+n=(x−2a)(x−2b)=x2−2(a+b)x+4ab, and m=−2(a+b) and n=4ab. Thus np=4ab−(a+b)=4mm2=8. Indeed, consider the quadratics x2+8x+16=0, x2+16x+64=0. If the roots of x2+mx+n=0 are 2a and 2b ...
1. A polynomial function of the 2nd degree has what form?y = ax2 + bx + c2. A quadratic equation has what form?ax2 + bx + c = 03. What do we mean by a root of a quadratic?A solution to the quadratic equation.4. A quadratic always has how many roots?
试题来源: 解析 su mofroots=2x+2β 4/1=2(d+β) x+β=2 p roducto+rwt_3=2d*2β 6/1=4dβ 6=4d αβ=6/4 α^3+β^3=(α+β)(α^2-αβ+β^2) =(2)[(2)^2-2(6/4)-6/4] =-1 α^3+β^3=-1 反馈 收藏
Quadratic Equation(二次方程式的问题)let k be a constant,if A and B are the roots of the equation x2 - 3x +k = 0,the A2 + 3B = ?k 是恒数,如果A和B是x 2- 3x+ k= 0的根,A2 + 3B = ? 相关知识点: 试题来源: 解析 因为A和B是x 2 - 3x+ k= 0的两个根,所以A+B=3,即B...
Let a be a constant. If the quadratic equation x2 ax a=1 has equal roots, then a=( ). 设a为一常数.若二次方程x2 ax a=1有等根,则a=( ). A. −1. B. 2. C. 0 or −4.0或−4. D. 0 or 4.0或4. 相关知识点: 试题来源: 解析 B x2+ax+a=1 x2+ax+a−1=0...