1+tan^(2) theta बराबर है- 01:36 सही शब्द /अंक से रिक्त स्थान की पूर्ति करें : pi एक …... संख्या है। 02:13 4x^(2) + (1)/(7) …...
View Solution tanθsecθ−1+tanθsecθ+1=2cosecθ View Solution Prove thattanθsecθ−1+tanθsecθ+1=2cosecθ View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
sec2(x)=1+tan2(x)csc2(x)=1+cot2(x)sin2(x)+cos2(x)=1 Answer and Explanation:1 Given Data: The given identity is:(secθ−1)(secθ+1)=tan2θ. Start with... Learn more about this topic: Verifying a Trigonometric Equation Identity ...
The rule is ddx(uv)=uv′+vu′ Now, you need to simplify the expression in the simplest form. Answer and Explanation: {eq}\displaystyle \frac{d}{d \theta} \bigg(\frac{\tan \theta}{1 + \theta^2 \tan \theta}\bigg)\ \Rightarrow \displaystyle \frac{(1 + \theta^2...
【解析】(1)$$ \overrightarrow { A B } = ( 1 , x ) , \overrightarrow { A C } = ( x + 2 \tan \theta , y + 1 ) $$ 且A,B,C三点共线; ∴$$ \overrightarrow { A B } / / \overrightarrow { A C } $$ ∴$$ y + 1 = x ( x + 2 t a n \t...
结果1 题目【题目】实式训练1设$$ \tan 2 \theta = 2 \sqrt { 2 } $$且$$ \theta \in ( \frac { \pi } { 2 } , \pi ) $$,求:(1)tanθ的值;2)年$$ \frac { \sin \theta + 2 \sin ^ { 2 } \frac { \theta } { 2 } - 1 } { \sqrt { 2 } \cos ( \f...
sin2(α)+cos2(α)=1cos(α)=1sec(α)sec(α)=1cos(α)tan(α)=sin(α)cos(α) Answer and Explanation: Given Data: We have given: θ=sec−1(−132). Simplify the function as: {eq}\begin...Become...
[(sec2 theta+1) sqrt(sec^2 theta-1)]xx1/2(cot theta- tan theta) ? View Solution If tan^4 theta+ tan^2 theta=1 then the value of cos^4 theta+cos^2 theta is यदि tan^4 theta+ tan^2 theta=1 हो, तो cos^4 theta+cos^2 theta का मान क...
cos15°+sin15°= Iftan2θtanθ=1, then the general value of z1 = 1/(z2)। z1 + z2 = 0। । যদি angleSBS^' সমকোণ হয়, তবে উপবৃত্তটির উৎকেন্দ্র হবে— ...
解析 【解析】∵$$ \tan \theta = 1 , $$ , ∴$$ \sin 2 \theta = \frac { 2 \sin \theta \cos \theta } { \sin ^ { 2 } \theta + \cos ^ { 2 } \theta } = \frac { 2 \tan \theta } { \tan ^ { 2 } \theta + 1 } $$. $$ = 1 $$ 故选:B. ...